Latest CTS Aptitude Question SOLUTION: B is 50% faster than A. If A starts at 9 A.M. and B starts at 10 A.M. A travels at a speed of 50 km/hr. If A and B are 300 kms apart, The time when they meet when they travel in o

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B is 50% faster than A. If A starts at 9 A.M. and B starts at 10 A.M. A travels at a speed of 50 km/hr. If A and B are 300 kms apart, The time when they meet when they travel in opposite direction is?

Asked In CTS (12 years ago)

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riya  (10 years ago)

let t be the elapsed time since A starts

50 t + 1.5*50(t-1) = 300

50 t +75 t = 300 + 75

t = 375 / 125 = 3 hrs past the time that A starts
so they meet at 12:00 noon

Is this solution Helpfull? Yes (6) | No (3)  

Simran  (10 years ago)

By 10 A.M., A had been traveling for 1 hr, covering a distance of 50 Km at 50 km per hr.
Speed of B=50+50%*50=50+25=75 km/hr
let x=travel time (hours) it would take for A & B to meet after 10 A.M.
(x+1) = total travel time (hours) of A

distance=speed*travel time
50(x+1)+75x=300
50x+50+75x=300
125x=250
x=2 hrs

The time when they meet when they travel in opposite directions is=10+2=12 noon

Is this solution Helpfull? Yes (5) | No (1)  

Devi  (9 years ago)

A 50 km/h
50% of A = 25 km/h
B travels at 75km/h
B starts at 10 am.
A starts at 9 am
A travels 50 km in 1 hour
when B starts they are 300 -50 km apart.
=250km.
Speed together = 50+75 = 125 km/h
Time = distance /speed
Time =250/125
Time = 2hours to meet.
They meet at 12.00 noon

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