Latest exam Aptitude Question SOLUTION: In studying the emission of light, in order to determine the angle at which the intensity is a giving value, the equation sin^2(A) - 4sin(A) + 1 = 0 must be solved. Find the angl

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(#M40072838) EXAM Numerical Ability question Keep an EYE

In studying the emission of light, in order to determine the angle at which the intensity is a giving value, the equation sin^2(A) - 4sin(A) + 1 = 0 must be solved. Find the angle A (to 0.1 of a degree). (sin^2(A) = (sinA)^2.: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: add express your answer in simpliest form x-13 over x^2-x-12 plus 3x-3 over x^2-x-12 A)3 over x-3 B)3 over x+4 C)4 over x-4 D)4 over x+3 Next Question: what is (8-the square root of 6)sqaured

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