Latest CTS Aptitude Question SOLUTION: AE BH CM DU? a)EH b)EZ c) EB d)None

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(#M40007294) CTS question Sequence problem Keep an EYE

AE BH CM DU?

a)EH
b)EZ
c) EB
d)None

Asked In CTS (12 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

amit kumar yadav  (9 years ago)

AE=1 5
BH=2 8
CM=3 13
DU=4 21

SEE D SECOND LETTER privious two addition comes next second letter
hence 13+21=34
i.e H

SO EH ans.

Is this solution Helpfull? Yes (9) | No (1)  

Mani kandan  (10 years ago)

i can't understand diff bw M & U =8.
becoz, diff bw E & H=2,H & M=4.this is ok.but not diff bw M & U=8, U & M.

Is this solution Helpfull? Yes (4) | No (1)  

kashif shaikh  (10 years ago)

answer should be UM i.e. none option d)
OBSERVE THE SECOND TERM OF EACH PAIR
DIFFERENCE BETWEEN E AND H IS OF 2 I.E 2^1 LETTERS
H AND M = 4 I.E 2^2 LETTERS
M AND U = 8 I.E. 2^3 LETTERS
THUS, AFTER DU EH WILL COME SINCE DIFFERENCE BETWEEN U AND H IS OF 2^4= 16 LETTERS.

Is this solution Helpfull? Yes (2) | No (6)  

guntur vineetha  (7 years ago)

First letter is in sequence A,B,C,D,E
The second letter sequence numbers will be in form of Fibonacci sequence E,H,M,U,H-5,8,13,21,34.

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