Latest CTS Aptitude Question SOLUTION: A group is divided into three. The first group is persons of 5'6 height and second and third r 6'0 and 6'6 respectively. There r totally 130 peoples, 50 of them r 5'6 and 65 of the

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(#M40007506) CTS question Numerical problem Keep an EYE

A group is divided into three. The first group is persons of 5'6 height and second and third r 6'0 and 6'6 respectively. There r totally 130 peoples, 50 of them r 5'6 and 65 of them r 6'6, 10 of them r 5'6 and 6'6, 15 of them r 5'6 and 6, 20 of them r 6'6 and 6, and 5 of them r all the three.
How many of them r 6 feet?

Asked In CTS (12 years ago)

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RAJASHEKAR RUDRARAPU  (10 years ago)

130-30-20-10=70

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shital  (10 years ago)

Ans=55

3 groups are A,B,C
n(A)=50 , n(C)=65
n(A intesection B)=15
n(A intesection C)=10
n(B intesection C)=20

130 = 50+65+n(B)-15-10-20+5
n(B)=55

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Mani kandan  (10 years ago)

total number of people=130
number of persons of height 5'6=50
number of persons of 6'6 height=65
number of people of 5'6 and 6'6 height=10
number of people of 5'6 and 6'0 height=15
number of persons of all 3 heights=5
number of people of height only 5'6=(number of people of height 5'6)-(number of people of all heights)- (number of people of heights 5'6 and 6'0)- (number of people of heights 5'6 and 6'6) =50-5-15-10=20

number of people of height only 6'6=(number of people of height 6'6)-(number of people of all heights)-(number of people of heights 6'0 and 6'6)=(number of people of heights 6'6 and 5'6)=65-5-20-10=30

number of persons of height 6 feet=(total number of people)-(number of people of heights only 5'6)-(number of people of heights only 6'6)-(number of people of heights 5'6 and 6'6)=130-20-30-10=70

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Vignesh  (12 years ago)

Solution : 15 of them are 6'0 height.
Explaina : Total number of peoples=130
Consider X as 5'6 height, X = 50
Y as 6'6 height, Y = 65
Z as 6'0 height, Z = ?
Therfore, Z= Total number of peoples - (X+Y)
= 130 - (50+65)
= 130 - 115
= 15

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