Latest L&T Aptitude Question SOLUTION: 27. In a rectangle the length is increased by of the original length. By what proportion should the width be reduced so that the area will be the same? Ans: 33

• Placement Papers
• /
• L&T
• /
• Numerical Ability
• /
• Percentage

L&T Question Papers: L&T Company Profile

(#M40007601) L&T Numerical Ability question Keep an EYE

27. In a rectangle the length is increased by of the original length. By what proportion should the width be reduced
so that the area will be the same?
Ans: 33

Asked In L&T (13 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (11)   (19) Submit Your Solution Percentage

Read Solution (5) :

A.P.Singh  (13 years ago)

statement is incomplete.
In a rectangle the length is increased by of the original length.

Here proportion of increase of length is not specified.
If length is increased by 100% of original length, new length will become double of original length.


If l and b are earlier length and breadth and
L and B are final length and breadth
then
l*b= L*B
l*b = 2*l*B
B= b/2

New width will be half of original width.

Is this solution Helpfull? Yes (20) | No (2)  

murthy  (11 years ago)

In the given problem length is increased by 50% so to get the same value breadth is decreased. 33 1/3%.

Is this solution Helpfull? Yes (4) | No (4)  

MOHAN  (8 years ago)

Assume the original Length and Breadth as 5 and 4. The area is 5 * 4 = 20.

The new length is 5 + 5 = 10. To retain the same area the breadth should be 2.

Breadth reduced from 4 to 2 or 50%

Is this solution Helpfull? Yes (1) | No   

Deenanath Mahato  (7 years ago)

assume length and width of rectangle are 'L' and 'W' .So area will be 'LW' .Now according to the condition
length is increased by the original length i.e. (L+L=2L).To make area equal to original area(LW) we need to half of width i.e. (W/2).

Is this solution Helpfull? Yes | No   

arivoli  (5 years ago)

Solution 1

Let length =
10

width
=
10

Then, area
=
10
×
10
=
100


New length
=
14

Therefore, new width
=
100
14


Decrease in width
=
10
−
100
14
=
20
7


Required percent
=
(
20
7
)
10
×
100
=
200
7
%
=
28
4
7
%

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.