Latest Wipro Aptitude Question SOLUTION: If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks at his usual speed how much time does he travels.

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If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks at his usual speed how much time does he travels.

Asked In Wipro Reck (13 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Sreenivasa Chowdary Nellore  (13 years ago)

If he walks at 4/5 of his usual speed he will take 5/4 of the usual time as speed and time are inversely proportional

Hence he is taking (1/4) of the time extra coz of which he is late

hence 1/4 of usual time = 40 min
usual time taken = 160 min

Is this solution Helpfull? Yes (29) | No (7)  

Rakesh Kumar Kohli  (13 years ago)

Ans. 160 minutes.

Let his usual speed is x and time taken is t minutes,
so distance travelled is xt.
If his speed is (4/5)*x then time taken is (t+40) minutes to cover the same distance.
therefore (4/5)*x (t+40)= xt => t/5 = 160/5
=> t = 160 minutes.

Is this solution Helpfull? Yes (22) | No (5)  

Vignesh  (13 years ago)

160 min or 2hr 40 min

(5/4) x - x = 40 min

1/4 x = 40 min

so x=160 min.

Is this solution Helpfull? Yes (14) | No (2)  

Reck  (13 years ago)

let d=distance
s=speed
t=time
so,(4*s)*(t+40)/5=st
4t+160=5t
t=160min

Is this solution Helpfull? Yes (4) | No (1)  

issac  (12 years ago)

160 minutes
distance d=speed*time
speed: y
time:x
normally d=xy;-------1
in particular time increases 40 min ie x+40
when speed=y(4/50
but d remains same
d=(x+40)(y4/5);------2
from 1&2
xy=(x+40)(y4/5)
=((x+40)*y4)/5
5xy=4xy+160y
5xy-4xy=160y
xy=160y
cancelling y both sides
x=160 minutes;

Is this solution Helpfull? Yes (4) | No (2)  

HIMANSHU GUPTA  (13 years ago)

Let d =dis. travelled (km)
u=usual speed(kmph)
t=time taken(hrs.) ....
So. d/u =t...............(1)
Also , d/(4u/5)=t+(40/60).......(2)

So from 1 & 2 :
d/u =8/3 or t=8/3 hrs = 8/3 * 60 min = 160 min

Is this solution Helpfull? Yes (3) | No (1)  

Shiv Kumar  (13 years ago)

Lets Say S is the Usual speed in KM per hour, T is the time in Minutes

person walks at 4/5th of his usual spee he reaches 40min late means Ditance = (4S/(5*60))*(T+40) ------ 1

he walks at his usual speed Distance becomes (S/60)*T -------2
Equating 1 and 2 time does he travels becomes 160 mins

Is this solution Helpfull? Yes (1) | No (4)  

Sayantan Dey  (6 years ago)

speed(decrease) = 1- (4/5) = 1/5
time(increase) = 1/(5-1)= 1/4
1/4 = 40 mins
1 = 160 mins

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