Latest TCS Aptitude Question SOLUTION: a is eating 27 chocolates in 60 min,b is eating 2 chocalates in 2 min, c is eating 7 chocalates in 20 min. inhow much time they can eat 120 chocalates

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a is eating 27 chocolates in 60 min,b is eating 2 chocalates in 2 min, c is eating 7 chocalates in 20 min. inhow much time they can eat 120 chocalates

Asked In TCS Surbhi Vyas (12 years ago)

Solved Shiv Kumar Read Solution (9)

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Read Solution (9) :

Shiv Kumar  (12 years ago)

A can eat 27 chocolates in 60 min
B is eating 2 chocalates in 2 min. means 60 chocolates in 60 min
C is eating 7 chocalates in 20 min. means 21 chocolates in 60 min
in 60 mins, all 3 eat 108 chocolates.
They can eat 120 chocalates in (120*60)/108 = 66.66667.
After converting decimal value to seconds (i.e. 0.6667*60) it becomes around 66 minutes 40 seconds

Is this solution Helpfull? Yes (27) | No (1)  

vikash kumar  (12 years ago)

in 60 minutes A can eat 27 choclates
in 1 minute A can eat 27/60 choclates
in 2 minutes B can eat 2 choclates
in 1 minutes B can eat 2/2 choclates
in 20 minutes c can eat 7 choclates
in 1 minutes c can eat 7/20 choclates
so for a+b+c in 1 minute total no of choclates are (27/60+2/2+7/20)
so a+b+c can eat 9/5 choclates in 1 minute
so a+b+c can eat 1 choclate in 1/(9/5) minute
so a+b+c can eat 120 choclates in (5/9)*120 minute
=66.66667 minutes so arround 66 mins and 40 seconds

Is this solution Helpfull? Yes (12) | No   

Insiya  (12 years ago)

66mins 40secs.
in 60 mins, all 3 eat 108 chocolates
in next 6 mins, the total becomes 118.8
n in next 40 secs they finish 120 chocs.
Thus total is 66 mins n 40 secs.

Is this solution Helpfull? Yes (3) | No (2)  

lakshman kumar aditya  (12 years ago)

it can be simply solved by using unitary method
27 cho.-60min
60 cho.-60min
21 cho.-60min
total 108 cho. are over so for 120...by unitary method
120*60/108=66.67

Is this solution Helpfull? Yes (2) | No (1)  

Rakesh Kumar Kohli  (12 years ago)

a eats 27 choclates in 60 minutes
So a will eat 1 choclate in 60/27 minutes
b eats 2 choclates in 2 minutes
b will eat 1choclate in 1 minute
So b will eat 60 choclate in 60 minutes
c eats 7 choclates in 20 minutes
c will eat 1 choclate in 20/7 minutes
So c will eat 21 choclate in 60 minutes
So a,b and c will simultaneously eat 108(27+60+21)choclates in 60 minutes.
As choclates will be given full (without breaking into pieces)to each of them.
So out of remaining 12 choclates we will give 7 choclates to a, 7 choclates to b and 2 choclates to c which they will all finish in minimum time of 7 minutes.
Thus they can eat 120 choclates in 67(60+7) minutes.

Is this solution Helpfull? Yes (1) | No   

aruna  (12 years ago)

Answer is 216 minutes

Is this solution Helpfull? Yes | No (10)  

kushal jain  (12 years ago)

i think it would be 81 minute nearly

Is this solution Helpfull? Yes | No (8)  

ravikumar  (12 years ago)

27= 60 min
60=60 min (1 per 1 min)
21=60 min (7 X 3)
totally 108 choco at 180 min
to eat 120 =108+12
ie
180+12=192 min

Is this solution Helpfull? Yes | No (3)  

simran gade  (12 years ago)

one minute work of
a=27/60 = 9/20
b=2/2 = 20/20
c=7/20
combined one day work of a, b and c = (9+20+7)/20
=36/20
=9/5
therefore, time req. by them to eat 120 chocolates= (5/9)*120 min.
= 4000 seconds.

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