Latest Capgemini Aptitude Question SOLUTION: In a race from pt. X to pt Y and back, Jack averages 0 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at

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In a race from pt. X to pt Y and back, Jack averages 0 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same tIme, who'll finish 1st
Jack/Sandy/they tie/Impossible to tell

Asked In Capgemini (12 years ago)

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Siddhartha Tarafder  (11 years ago)

The question will be
In a race from pt. X to pt Y and back, Jack averages 30 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same tIme, who'll finish 1st.

Sandy won the race.

Jack: Runs at 30 mph to Y and at 10 mph back to X. So his avg. speed is given by the formula (2ab)/(a+b) i.e. 15 mph

Sandy: Runs at 20 mph to Y and at 20 mph back to X. So his avg. speed is 20 mph


So only Sandy wins the race.

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Harsh Gupta  (11 years ago)

Jack will finish first because starting and ending both point are same and here Jack is static by nature so he will finish first

Is this solution Helpfull? Yes (11) | No (43)  

ROHIT GUPTA  (7 years ago)

quesyion incomplete ????? 30????

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Prabhanjan  (7 years ago)

Sandy is first

Is this solution Helpfull? Yes (2) | No (1)  

sree sravya  (8 years ago)

d= distance
Jack's time = d/30 + d/10 = 4d/30 = 2d/15 = 0.1333... d
Sandy's time = d/20 + d/20 = d/10 = 0.1d
so finally they tie
ans : option 3

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