Latest Hexaware Aptitude Question SOLUTION: Find the probability that a five digit no formed by 1,2,3,4,5 ( not repeated) are divisible by 4.

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Find the probability that a five digit no formed by 1,2,3,4,5 ( not repeated) are
divisible by 4.

Asked In Hexaware (12 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

Chandan Saha  (12 years ago)

a number is divisble by 4 only when the last 2 digit can be divided by 4..and so in this case it is possible when last two digits are 12,32,24,52.and for that the probability will be 24/120=1/5...

Is this solution Helpfull? Yes (11) | No (9)  

rajesh ray  (10 years ago)

last two digits must be,
***12
***24
***32
***52
case1) ***12
rest three digits can be filled in 3*2*1 or 6 ways
similarly,
case2) ***24
6 ways
case3) ***32
6ways
case4) ***52
6 ways
total required ways = 6*4 = 24
total arrangements = 5*4*3*2*1 = 120

probability = 24/120 = 1/5

Is this solution Helpfull? Yes (7) | No   

lavanyadevi  (12 years ago)

digits which r divisble by 4 are 12,24,32,52 (last 2 digits should divided by 4)
4!/5! = 24/120 =1/5...............

Is this solution Helpfull? Yes (5) | No (2)  

arjun  (12 years ago)

24/120 how?

Is this solution Helpfull? Yes (4) | No (2)  

Vaibhav Bhagwan Dhonde  (10 years ago)

digits which r divisble by 4 are 12,24,32,52 (last 2 digits should divided by 4)
then remaining digits r 3 ...(3!*2!*1!)*4 (possibilities)=48
so,prob=48/5! (total 5 digits nos)
ans=2/5

Is this solution Helpfull? Yes (2) | No (4)  

RAMKOSAL  (11 years ago)

N^n-1
N=no of digits in series
n=no of digits to ask
ans=625

Is this solution Helpfull? Yes | No (7)  

Niranjan Kumar  (8 years ago)

(n-1)!/n!=?
(5-1)!/5!=24/120=1/5

Is this solution Helpfull? Yes | No   

GopalaRao  (8 years ago)

24/120=1/5

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Rishi Raj  (5 years ago)

5!*4!*3!*2!*1

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