Latest CTS Aptitude Question SOLUTION: Ravi has a bag full of 10 Nestle and 5 Cadbury chocolates. Out of these, he draws two chocolates. What is the probability that he would get at least one Nestle Chocolate ? 1) 19/2

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Ravi has a bag full of 10 Nestle and 5 Cadbury chocolates. Out of these, he draws two chocolates. What is the probability that he would get at least one Nestle Chocolate ?

1) 19/21
2) 3/7
3) 2/21
4) 1/3

Asked In CTS R Chauhan (10 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

Munirasu  (10 years ago)

Total number sample space two chocolates can be drawn in the way of n(S) = 15C2= 105
At least one to be nestle.. n(E) = 10C1 X5C1 + 10C2 X 5C0 = 95
P(E) = 95/105 = 19/21

Is this solution Helpfull? Yes (35) | No   

jyotsna kumari  (10 years ago)

(10c1*5c1+10c2)/15c2=19/21

Is this solution Helpfull? Yes (9) | No (1)  

Prashant Tripathi  (9 years ago)

it can b done as follows....
(1Nestle and 1Cadbury) or (1Cadbury and 1Nestle) or (2Nestle) i.e.
(10/15 * 5/14) + (5/15 * 10/14) + (10/15 * 9/14) on solving....
5/21 + 5/21 + 3/7 which on solving will give ans as 19/21 :)

Is this solution Helpfull? Yes (6) | No   

rajeswari  (10 years ago)

a)19/21
is right anwer

Is this solution Helpfull? Yes (2) | No (3)  

NIKHIL KUMAR SINGH  (9 years ago)

10C2/15C2=3/7

Is this solution Helpfull? Yes (1) | No (7)  

Sweety Rupnar  (9 years ago)

(10c2)+(10c1*5c1)=95/105=19/21

Is this solution Helpfull? Yes (1) | No   

Rahul Nagwani  (9 years ago)

A)19/21



we use combination

Is this solution Helpfull? Yes (1) | No   

Abideepika  (8 years ago)

the probability of getting atleast one chocolate is
(10C1*5c1)+10c2/15c2=19/21

Is this solution Helpfull? Yes (1) | No   

lakshmi kattamuri  (10 years ago)

Have any one got the online test result of Cognizant through amcat held at st.peters engg. College, Hyderabad fr 2014 batch on 29th december

Is this solution Helpfull? Yes | No (5)  

Radhesyam  (8 years ago)

[(10c1*5c1)/15c2]+[(10c2/15c2)]=19/21

Is this solution Helpfull? Yes | No   

alpa sharma  (8 years ago)

option 1
10c1 * 5c1/ 15c2 + 10c2/15c2
on solving this we get 19/21

Is this solution Helpfull? Yes | No   

Dipankar Modak  (8 years ago)

Total probability-no Nestle chocolate=1-5c2/15c2=19/21

Is this solution Helpfull? Yes | No   

Soham Hazra  (5 years ago)

Choosing no nestle chocolate -> choosing 2 cadbury / choosing 2 chocolates from total chocolates
-> 5 C 2 / 15 C 2
-> 2/21
Choosing atleast 1 nestle -> 1 - choosing no nestle
-> 1- 2/21
-> 19/21
( ans ) 19/21

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