Latest exam Aptitude Question SOLUTION: Example: P=P0[1+r]^t what is: in 2009 is p1=60,943,912[1+0.9934]^(1) in 2010 is p2=60943,912[1+0.9934]^2 I need the same answer for 2011 and 2012 please explain and show me ho

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(#M40084568) EXAM Numerical Ability question Keep an EYE

Example: P=P0[1+r]^t

what is:
in 2009 is p1=60,943,912[1+0.9934]^(1)
in 2010 is p2=60943,912[1+0.9934]^2

I need the same answer for 2011 and 2012 please explain and show me how to figure this our.

Asked In exam (9 years ago)

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