Latest self Aptitude Question SOLUTION: A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the

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A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A. 2 : 1 B. 3 : 2
C. 25 : 18 D. 27 : 20

niru (12 years ago)

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Sanjana Patnaik  (12 years ago)

Ans: Option C=25:18
The total volume of the smaller cubes=216 cm^3(3^3+4^3+5^3)
Now, the side of the bigger cube is 6cm
The total surface area of the smallers cubes= 300 cm^2(6*3^2+6*4^2+6*5^3)
The total surface area of the bigger cube= 216 cm^2(6*6^2)
Now the ratio as asked is 300cm^2:216 cm^2=25:18

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Satish Reddy  (10 years ago)

Volume of the large cube = (33 + 43 + 53) = 216 cm3.

Let the edge of the large cube be a.

So, a3 = 216 a = 6 cm.

Required ratio = 6 x (3^2 + 4^2 + 5^2) / 6*(6^2) = 25 : 18.

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