I need help For the following problem I found no solution 2log2 x 6 log2 16 2 heres my work

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The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

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Latest exam Aptitude Question SOLUTION: I need help. For the following problem I found no solution: 2log2 (x+6) - log2 16 = 2 heres my work: log2 x^2+36-16 = 2 x^2+20 = 2^2 x^2+20 = 4 x^2=-16 then there is no real

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