Latest Wipro Aptitude Question SOLUTION: 9 In a examination, 80% of the students passed in English, 85% in mathematics and 75% in both English and mathematics. If 40 students failed in both the subjects, the total numbe

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9
In a examination, 80% of the students passed in English, 85% in mathematics and 75% in both English and mathematics. If 40 students failed in both the subjects, the total number of students is?

Asked In Wipro rakesh bugudi (12 years ago)

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Read Solution (6) :

Vignesh  (12 years ago)

Total number of Students = 400

Let the total number of students = x
Let Students passed in English = A
And Students passed in Maths = B
Number of students passed in one or both the subjects = n(A?B)
=n(A)+n(B)- n(A?B)
=80% of x + 85% of x –75% of x
=[(80/100)x+(85/100)x-(75/100)x]
=(90/100)x
=(9/10)x

Students who failed in both the subjects = [x-(9x/10)]
= x/10.

Therefore, x/10= 40 of x =400
Total number of students = 400.

Is this solution Helpfull? Yes (31) | No   

dhivya  (12 years ago)

lets total number of student be x
let A and B are passed in english and maths.. A=80% and B=85%..
then the numeber of student passed in both the sub is 75%
n(AUB)=n(A)+n(B)-n(AnB)=(80/100x + 85/100x - 75/100x)
=> 90/100x
=> 9/10x...
student failed in both the sub=(x-9x/10)
=> x/10
so,x/10=40
x=400 student

Is this solution Helpfull? Yes (13) | No (1)  

urep  (11 years ago)

The total is 100%
in English 80% and Maths 85% ,Both 75%
we Need the percentage of students who Passed in the examination

n(A)+n(B)-n(A intersection B)

so (80% +85% )- 75% = 90%
90 % of students passed in the examination

the total is 100% where the passed students 90%
so failed students 100%-90% =10%

we know failed students=40

A 10% of total students(X) =40 ,X we assume it as a total students

X *10% =40
so
X*10/100=40 percentages method.

X=40*100/10

X=400

so the total students is 400

Is this solution Helpfull? Yes (8) | No   

sowmya.B.J  (12 years ago)

ans:130
total no. of students who pased=80+85-75=90
total no. of students who failed =40
total no.of students=pass+fail=130

Is this solution Helpfull? Yes (4) | No (15)  

anannya mazumder  (11 years ago)

Let the total number of students be x .
Let A and B represent the sets of students who passed in English and Mathematics respectively .
Then , number of students passed in one or both the subjects
= n(AÈB)=n(A)+n(B)- n(AÇB)=80% of x + 85% of x –75% of x
=[(80/100)x+(85/100)x-(75/100)x]=(90/100)x=(9/10)x
Students who failed in both the subjects = [x-(9x/10)]=x/10.
So, x/10=40 of x=400 .
Hence ,total number of students = 400.

Is this solution Helpfull? Yes (2) | No   

Ankit  (9 years ago)

80%of x+85%of x -75%of x=9/10x
students who fail in both the subjects=x-9/10x=x/10
As, 40=x/10 since 40 students failed in both subjects

total number of students=400

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