Latest Others Aptitude Question SOLUTION: Can you find the values of integers a, b, c so that a/b + b/c + c/a an integer. where a# b#c means a,b,c are not equal to each other.

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(#M40009071) OTHERS question abc puzzle Keep an EYE

Can you find the values of integers a, b, c so that a/b + b/c + c/a an integer.
where a# b#c
means a,b,c are not equal to each other.

Asked In Others Bankim (12 years ago)

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Vignesh  (12 years ago)

Having Lot of Possibilities.

One of those are,

a = 4; b = 8; c = 2;
Therefore,

=> (a/b)+(b/c)+(c/a) = (4/8)+(8/2)+((2/4)
=> 0.5 + 4 + 0.5
=> 5
All are integers.

Is this solution Helpfull? Yes (3) | No (1)  

Vignesh  (12 years ago)

Possibles of a,b,c are

a=4; b=8; c=2;==>(a/b)+(b/c)+(c/a) = (4/8)+(8/2)+(2/4) ==> 0.5 + 4 + 0.5 ==> 5

a=8; b=2; c=4;==>(a/b)+(b/c)+(c/a) = (8/2)+(2/4)+(4/8) ==> 4 + 0.5 + 0.5 ==> 5

a=2; b=4; c=8;==>(a/b)+(b/c)+(c/a) = (2/4)+(4/8)+(8/2) ==> 0.5 + 0.5 + 4 ==> 5

All values of a,b,c and answer will be integers.

Is this solution Helpfull? Yes (3) | No (1)  

Vignesh  (12 years ago)

Possible Values can be calculated by following eqn.

If, a = x; b = 2(x); c = 2(b); Or
If, b = x; c = 2(x); a = 2(c); Or
If, c = x; a = 2(x); b = 2(a);

By Putting x= any integer except 0, we find so many possibilities of values.

Is this solution Helpfull? Yes (2) | No   

Tousifahmad  (12 years ago)

a=1,b=2,c=4
(a/b)+(b/c)+(c/a)=(1/2)+(2/4)+(4/1)=0.5+0.5+4=5

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