Latest exam Aptitude Question SOLUTION: Divisions 8x^3 - 6x^2 + 2x/ 4x + 1

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Previous Question: I am stuck with this problem. Please help. The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the lengths of the equal legs. Next Question: determine the range for:f(x)=9-8x-x^2

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8x^3 - 6x^2 + 2x/ 4x + 1: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: I am stuck with this problem. Please help. The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the lengths of the equal legs. Next Question: determine the range for:f(x)=9-8x-x^2

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