Latest Infosys Aptitude Question SOLUTION: My Dad has a miniature Pyramid of Egypt. It is 3 inches in height. Dad was invited to display it at an exhibition. Dad felt it was too small and decided to build a scaled-up model

• Placement Papers
• /
• Infosys

Infosys Question Papers: Infosys Interview Experience(10) INFOSYS Company Profile

(#M40009537) INFOSYS question Pyramid Keep an EYE

My Dad has a miniature Pyramid of Egypt. It is 3 inches in height. Dad was invited to display it at an exhibition. Dad felt it was too small and decided to build a scaled-up model of the Pyramid out of material whose density is (1 / 10) times the density of the material used for the miniature. He did a "back-of-the-envelope" calculation to check whether the model would be big enough.

If the mass (or weight) of the miniature and the scaled-up model are to be the same, how many inches in height will be the scaled-up Pyramid? Give your answer to two places of decimal.

Asked In Infosys Nikhil Patel (12 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (5)   (1) Submit Your Solution

Read Solution (3) :

Aman  (12 years ago)

6.45 inches

Volume of model / Volume of miniature = (Ht. of model / Ht. of miniature)^3.
Mass = Density x Volume;
when mass remains same, Density and volume are inversely proportional.
Volume of model / Volume of miniature = (Height of model / Height of miniature)^3 = Density of miniature/density of model

Height of model = Height of miniature*(Density of miniature/density of model)^(1/3) = (3)*[(10)^(1/3)] = 3*2.15 = 6.45 inches

Is this solution Helpfull? Yes (4) | No (1)  

rahul.r.kalwar  (12 years ago)

b4 solving such questions have a closer look over statements they are so simple,
one should know that "volumes is directly propotional to the cube of height of a geometrical similar objects"
density=mass/volume.
Given:
1.height of pyramid=3 inches
2.density_of_material=1/10 density_of _material_of _pyramid
3.mass(weight) remains constant
To find:
height of new object.
from above,
(volume of miniature pyramid)/(volume of material)= (height of pyramid)/(height of material)^3.
ok now we know that mass remains constant (d=m/v) so we have relation of density
inversly propostional to the volume tht gives us
density of material used/density of pyramid=(ht of pyramid)^3/(ht of material used)^3
1/10=9/x^3
x^3=90
x=4.481405
ht of scaled up =4.4814

Is this solution Helpfull? Yes (2) | No (1)  

Nikhil Patel  (12 years ago)

It is important to note that
Mass = Density × Volume; and
Volume of model / Volume of miniature = (H of model / H of miniature)3.

In the above equation, H is the characteristic dimension (say, height).

If the mass is to be the same, then density is inversely proportional to volume. Also, the volumes are directly proportional to the cubes of the heights for objects that are geometrically similar. Therefore, the heights are seen to be inversely proportional to the cube roots of the densities. Thus,

Height of model = Height of miniature × (Density of miniature / Density of model)1/3 or

Height of model = 3 × 101/3 = 6.46 inches.

Food for thought:

The above analysis was done for a simple geometry (e.g., pyramid)? Does such an analysis hold for complex shapes?

A lot of scientific and engineering studies are done with scaled-up models (for microscopic phenomena) and scaled-down models (e.g., wind tunnel experiments in aerodynamics). Dimensional Analysis (used above) and Similarity are important concepts in such studies.

Is this solution Helpfull? Yes (1) | No (1)  

Please Login to Read Solution.