Latest CAT Aptitude Question SOLUTION: A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type

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A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206.

Find the number of coins of each type

Asked In CAT kumar (12 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

asim  (12 years ago)

let ratio be x,
hence no. of coins be 5x ,9x , 4x respectively
now given total amnt = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
=> on solving
we get x = 40
=> no. of 50p coins = 200
=> no. of 25p coins = 360
=> no. of 10p coins = 160

Is this solution Helpfull? Yes (19) | No (1)  

chaitanya  (12 years ago)

Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) = 206
50x + 45x + 8x = 4120
1O3x = 4120
x = 40.

Number of 50 p coins = (5 x 40) = 200;
Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160.

Is this solution Helpfull? Yes (10) | No (7)  

sagar arora  (12 years ago)

let 50p,25p and 10p coins be 5x,9x & 4x respc.
now divide the no. of coins by their denomination related to the rupee
So,
(5x/2)+(9x/4)+(4x/10)=206
50x + 45x + 8x =206*20
1O3x =206*20
therefore,
x = 40.
Therefore,
50p coins=(5 x 40)=200;
25p coins=(9 x 40)=360;
10p coins=(4 x 40)=160.

Is this solution Helpfull? Yes (8) | No (5)  

RUDRA KRISHNA KUMAR J  (12 years ago)

50p-200,25p-360,10p-160

Is this solution Helpfull? Yes | No (1)  

Aman  (12 years ago)

Good observation by Vignesh.

Is this solution Helpfull? Yes | No   

Chirag Ranjan Lahiri  (10 years ago)

et ratio be x,
hence no. of coins be 5x ,9x , 4x respectively
now given total amnt = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
=> on solving
we get x = 40
=> no. of 50p coins = 200
=> no. of 25p coins = 360
=> no. of 10p coins = 160

Is this solution Helpfull? Yes | No   

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