Latest exam Aptitude Question SOLUTION: 3/(x^2+4x+3) - 1/(x^2-9) =3/(x+1)(x+3)-1/(x-3)(x+3) =(3((x-3)-1(x+1))/(x+1)(x-3)(x+3) =3x-3-x-1/(x+1)(x^2-9) =2x-4/(x^3+x^2-9x-9) =2(x-2)/(x^3+x^2-9x-9)

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(#M40097952) EXAM Numerical Ability question Keep an EYE

3/(x^2+4x+3) - 1/(x^2-9)
=3/(x+1)(x+3)-1/(x-3)(x+3)
=(3((x-3)-1(x+1))/(x+1)(x-3)(x+3)
=3x-3-x-1/(x+1)(x^2-9)
=2x-4/(x^3+x^2-9x-9)
=2(x-2)/(x^3+x^2-9x-9)

Asked In exam (9 years ago)

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