Latest exam Aptitude Question SOLUTION: how would i solve these using factoring :D . 1- (x - 2)(2x - 5) = 0 2- x^2 + 6x - 27 = 0 3- x^2 + 6 = -5x

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(#M40099073) EXAM Numerical Ability question Keep an EYE

how would i solve these using factoring :D .

1- (x - 2)(2x - 5) = 0


2- x^2 + 6x - 27 = 0


3- x^2 + 6 = -5x

Asked In exam (9 years ago)

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