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Frequently Asked CSC Numerical Ability - Boats and Streams Interview Questions with Answers

(#M40003825) CSC QUESTION csc latest puzzle Keep an EYE

A boat covers a distance of 30 kms in 2 ½ hours running down streams. While returning, it covers the same distance in 3 ¾ hours. What is the speed of the boat in kmph?

a) 12 b)8 c) 14 d) 10

Asked In CSC (13 years ago)

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(#M40003827) CSC QUESTION csc latest puzzle Keep an EYE

A boat can row 18 kmph in still water.It takes twice as long to row up as to row down the river.Find the rate of stream.

a)6 km/hr b)7 km/hr c) 8km/hr d)5 km/hr

Asked In CSC (13 years ago)

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(#M40003826) CSC QUESTION csc latest puzzle Keep an EYE

A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current.

a) 8 km/hr, 1 km/hr b)5 km/hr, 4 km/hr c) 1 km/hr, 6 km/hr d)2 km/hr, 1 km/hr

Asked In CSC (13 years ago)

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(#M40003946) CSC QUESTION csc latest puzzle Keep an EYE

Let a boat traveling in still water with a speed of 30 kmph covers a certain distance in 9 hours. Now if the same distance has to be covered traveling upstream in a speed of 10 Kmph, by what percentage the speed of the boat should be increased to cover the distance in the same time of 9 hours.

a. 33.33% b. 66.66% c. 24.47% d. 60%

Asked In CSC (13 years ago)

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(#M40003945) CSC QUESTION csc latest puzzle Keep an EYE

Two boats A and B of engine speed u travel in opposite directions in a stream of speed a. Let A travel in the direction of stream. Let the distance between them be s. What time they will cross each other.

a. s/(2u) b. (2s)/u c. can't be determined d. s/u

Asked In CSC (13 years ago)

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(#M40003944) CSC QUESTION csc latest puzzle Keep an EYE

A boat with still water speed of a is traveling upstream where the streams speed is b. After covering certain distance s, the boat turns back and tries to come to the starting place. But the boat stops at 3/4th of the intended distance due to a technical fault. What is the ratio of the time taken for the return journey to that of the upstream journey.

a. 3(a - b)/4(a + b) b. 4(a - b)/3(a + b) c. 3(a + b)/4(a - b) d. 4/3

Asked In CSC (13 years ago)

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