Can you find a five digit number that, if you place a 9 at the beginning to make a new number, is fours times larger than if you place the 9 at the end instead?
Solution
Let the number is 10000x+1000y+100z+10p+q
now according to the given condition
100000*9+10000x+1000y+100z+10p+q = 100000x+10000y+1000z+100p+10q+9
on solving we get 10000x+1000y+100z+10p+q = (900000-36)/39 = 23076
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