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(#M40033887) TCS QUESTION TCS Keep an EYE

Summation from i=0 to 6409 of ai = ?
where ai= 29(if ai is divided by 13 & 17)
ai= 17(if ai is divided by 13 & 29)
ai= 13(if ai is divided by 17 & 29)
ai=0 (else)

Asked In TCS sree (11 years ago)

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(#M40033883) SELF QUESTION Keep an EYE

A person leaves his home at a time when hour hand is between 4-5 and minute hand between 5-6, and when he returns after some time, the hands exchanged their positions. What time did he leave at?

SONU GUPTA (11 years ago)

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(#M40033882) SELF QUESTION Keep an EYE

Find the number of zeroes in 100^1! *99^2! *98^3! *..... 1^100

SONU GUPTA (11 years ago)

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(#M40033880) SELF QUESTION Keep an EYE

A can solve a problem is 6/7 and B solving the problem is 3/14. Assuming two events 'A can solve the problem' and 'B can solve the problem' r independent,,, probability that only one can solve the problem
Option
1. 3/28
2. 5/28
3. 9/28

SONU GUPTA (11 years ago)

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(#M40033878) SELF QUESTION Keep an EYE

What is the max. Possible integer value of p if
7*8*9*.........*135=n*720^p

1. 30
2. 31
3. 32
4. 33

SONU GUPTA (11 years ago)

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(#M40033876) SELF QUESTION Keep an EYE

There r 2 balls in a box, whose colours r nt known except that both may b red or both white or one red and one white,, one more white ball of same size added to the lot,, nw one ball is drawn at random frm the box, then the probability that it is white

SONU GUPTA (11 years ago)

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(#M40033874) TCS QUESTION no.of zeros Keep an EYE

number of zeros in 1*2^2*3^3*4^4*....49^49

Asked In TCS santhoshi (11 years ago)

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(#M40033870) ACIO QUESTION igigigi Keep an EYE

gig ig I I I

Asked In ACIO (11 years ago)

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(#M40033860) TCS QUESTION puzzzle Keep an EYE

14 people meet and shake hands . The maximum number of handshakes possible if there is to be no “ cycle” of handshakes is ( A cycle of handshakes is a sequence of people a1,a2,a3……ak k>2) such that pairs {a1,a2}……{ak,a1} shake hands)
Option
a) 11
b) 12
c) 10
d) 13

Asked In TCS ADIL (11 years ago)

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(#M40033856) TCS QUESTION Keep an EYE

For all positive Integers n Less than 17329, define
13 for n divisible by 31 and 43
a n = 31 fro n divisible by 31 and 43
43 for n divisible by 13 and 31
0 otherwise

What is the value of
17329
an n=1
Option
a. 2295
b. 17329
c. 2892
d. 1738

Asked In TCS RAvi (11 years ago)

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