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(#M40016444) MBA QUESTION number systems, progressions Keep an EYE Keep an eye puzzle Keep an eye puzzle

What is the highest possible value of ‘n’ for which 3^(1024) – 1 is divisible by 2^n?

1) 13
2) 10
3) 11
4) 12

Asked In MBA (12 years ago)
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(#M40016443) MBA QUESTION algebra, quadratic equations, inequalities, functions Keep an EYE Keep an eye puzzle Keep an eye puzzle

Find the area bounded by y=|x-1| and y=3-|x| ?

1) 2.5
2) 4
3) 6
4) 8

Asked In MBA (12 years ago)
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(#M40016445) MBA QUESTION algebra, quadratic equations, inequalities, functions Keep an EYE Keep an eye puzzle Keep an eye puzzle

In 1937, Ashish stated that, he was x years old in the year x^2. If the number of his years be added to the number of his birth month, the result equals the square of the day of the month on which he was born.When was he born?

1) 6.11.1892
2) 6.11.1891
3) 5.7.1892
4) 7.5.1893
5) 7.5.1892

Asked In MBA (12 years ago)
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(#M40016446) MBA QUESTION mensuration, geometry & co-ordinate geometry Keep an EYE Keep an eye puzzle Keep an eye puzzle

Aright circular cone of height h is cut by a plane parallel to the base at a distance h/3 from the base, then the volume of the resulting cone the frustrum are in ratio:

1) 1:3
2) 8:19
3) 1:4
4) 1:7

Asked In MBA (12 years ago)
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(#M40016447) MBA QUESTION algebra, quadratic equations, inequalities, functions Keep an EYE Keep an eye puzzle Keep an eye puzzle

x and y are natural numbers such that they satisfy the equation x + y + 31 = 2xy. Find the maximum possible integral power of 6 in (xy)!.[n! is the product of the first ‘n’ natural numbers.] let me know the procedure also...

1) 11
2) 15
3) 14
4) 16

Asked In MBA (12 years ago)
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(#M40016449) MBA QUESTION number systems, progressions Keep an EYE Keep an eye puzzle Keep an eye puzzle

S=1!+2!+3!+...+n!can somebody tell me the sum of this series i mean in the form of n.

1) I am tired of life.
Please don't look for me.
2) Chalta hu mein...BYE !!!
3) Bi**h Please

Asked In MBA (12 years ago)
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(#M40016450) MBA QUESTION mensuration, geometry & co-ordinate geometry Keep an EYE Keep an eye puzzle Keep an eye puzzle

ABC is a triangle given that angle B is equal to 2x and angle C is equal to x. AD is the angle bisector of angle A on line BC.Given that side AB=DC find angle BAC.

1) 36
2) 72
3) 144
4) None of these.

Asked In MBA (12 years ago)
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(#M40016451) MBA QUESTION number systems, progressions Keep an EYE Keep an eye puzzle Keep an eye puzzle

Find the product of all the factors of 3^16a) 3^33 b) 3^68 c) 3^136 d) 3^128

1) a
2) b
3) c
4) d

Asked In MBA (12 years ago)
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(#M40016453) MBA QUESTION algebra, quadratic equations, inequalities, functions Keep an EYE Keep an eye puzzle Keep an eye puzzle

The equation of the form x2 + 1 = 0 or x2 + y = 0 etc. are not solvable in R (set of real numbers) i.e. there is no real number whose square is a negative real number. If the symbol ‘i’ is written for the square root of –1 with the property i2 = –1 then find the square roots of –15 – 8i.

1) 1 + 4i
2) –1–4i
3) ± (1 – 4i)
4) None of these

Asked In MBA (12 years ago)
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(#M40016452) MBA QUESTION algebra, quadratic equations, inequalities, functions Keep an EYE Keep an eye puzzle Keep an eye puzzle

Hey!! guys.. please help me understand this Q.Q. Find the remainder when [{(300)^3000} -1] is divided by 1001.Now, the problem is.. I tried to approach the Q. by Remainder Theorem but to no avail. I couldnt solve by it. The solution is given by expressing every thing in terms of mod. I guess I have never learnt the mod approach of solving problems and may be I am sort of not wanting to learn a different approach apart from the regular one.. Please if you can help me understand the "mod" way in remainders and how to solve it by the Remainder Theorem.

1) 0
2) 1
3) 2
4) 3
5) None of These

Asked In MBA (12 years ago)
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