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(#M40000626) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

7. Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?



(a) Rs. 22,781.25 (b) Rs. 24,150.25 (c) Rs. 28,140.50 (d) Rs. 18,000

Asked In TCS anuj (14 years ago)
Solved Pritam Kumar Paul Read Solution (1)
Is this Puzzle helpful?   (4)   (2) Submit Your Solution Age Problem

(#M40000560) INFOSYS QUESTION find the number of man Keep an EYE Keep an eye puzzle Keep an eye puzzle

There were totally 100 men.85 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?

Asked In Infosys Aditi Sharma (14 years ago)
Solved Suman Read Solution (2)
Is this Puzzle helpful?   (6)   (0) Submit Your Solution Number System
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(#M40000557) INFOSYS QUESTION language puzzle Keep an EYE Keep an eye puzzle Keep an eye puzzle

B and C initially speak English but when D joined Spanish they too took up Spanish. The only common language between A, B and E is French. The only common language between C and E is Italian. Three people speak Portuguese. Most common language is Spanish. One person knows all the 5 language, one person knows 4 languages, one person knows 3 languages, one person knows 2 languages and one person knows only one language.

Asked In Infosys Aditi Sharma (14 years ago)
Unsolved Read Solution (5)
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(#M40000559) INFOSYS QUESTION match puzzle Keep an EYE Keep an eye puzzle Keep an eye puzzle

There was a match to be held.And 100 nations were to participate in that match.It was totally an elimination match,that is if a team loses a match it must be eliminated.Find out the total number of matches played to find out the grand winner?

Asked In Infosys Aditi Sharma (14 years ago)
Solved Suman Read Solution (3)
Is this Puzzle helpful?   (6)   (1) Submit Your Solution Permutation and Combination

(#M40000648) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it
hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery?
option
a) 0.75
b) 1
c) 0.5
d) 0.25

Solution
Since according to requirement we have to locate Q closer to center in comparison to the circumference, for doing this we shall make a circle in that board whose radius will be half of the radius of dartboard.now we will compare the area of inner circle to the total area
Answer of DIPIN is correct
area of whole circle = pi*(1 foot)^2 = pi (this is according to formula area = pi*(radius)^2
similarly area of inner circle = pi*(1/2foot)^2 = pi/4
so ratio of areas of these two circles will be the probability and that is 1/4


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Asked In TCS Bhavani (14 years ago)
Solved Read Solution (3)
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(#M40000645) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
option
a) 1
b) 3
c) 4
d) 0

Solution
Answer will be (c)
There will be four points satisfying the given condition
one point will be incentre of the circle and other three will be excentres


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Asked In TCS (14 years ago)
Solved Read Solution (4)
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(#M40000605) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

1! + 2! +......... + 50!=?
a)3.1035*10^64
b)2.1021*10^65
c)3.1035*10^63
d)3.1035*10^62

Solution
solve 50! + 49! + 48!
others are lower terms
this can be done by calculator only

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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved SANTOSH AGRASINGH Read Solution (2)
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(#M40000604) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Given a collection of points P in the plane , a 1-set is a point in P that can be separated from the rest by a line, .i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e no three points in P lie on a line) is
a) 3
b) 5
c) 2
d) 8

Solution
The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3


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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Read Solution (5)
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(#M40000583) ORKUT QUESTION Values of numbers Keep an EYE Keep an eye puzzle Keep an eye puzzle

Q. Four whole numbers - a, b, c and d.
such that -
1. ( a + b + c + d ) is a perfect square
2. ( a + b ), ( a + c ), ( a + d ), ( b + c ) , ( b + d ) and ( c + d ) are also each a perfect square. What are the smallest values for a, b, c and d?

Asked In Orkut Dr.Dipin Singh (14 years ago)
Unsolved
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(#M40000178) GENERAL QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

How many possible combinations are there in a 3x3x3 rubics cube?
In other words, if you wanted to solve the rubics cube by trying different combinations, how many might it take you (worst case senerio)?
How many for a 4x4x4 cube?

Asked In general Naveen (14 years ago)
Unsolved
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