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(#M40010315) M4MATHS QUESTION diagonal sum Keep an EYE Keep an eye puzzle Keep an eye puzzle

Place the numbers 1 through 100 on a 10x10 square table so that all consecutive numbers will be on adjacent (right, left, up, down) squares. What will be the maximum value of the sum of the 10 numbers along a diagonal of this table?

Asked In m4maths Aman (13 years ago)
Unsolved
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(#M40010114) M4MATHS QUESTION number of weighings Keep an EYE Keep an eye puzzle Keep an eye puzzle

There are 50 coins. Half of them are genuine and the other half are counterfeit. Genuine coins weigh 10 grams, while counterfeit coins differ from the genuine coins by 1 gram (some of them weigh 9 grams, and some of them weigh 11 grams). You have a balance scale with two pans. In each weighing the scale shows the difference of the weights placed in each pan. You will randomly choose a coin. What is the minimum number of weighings necessary to guarantee to determine whether it is genuine or not?

Asked In m4maths Brij (13 years ago)
Unsolved Read Solution (1)
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(#M40010037) M4MATHS QUESTION words Keep an EYE Keep an eye puzzle Keep an eye puzzle

Pls check the solution for puzzle

Total no. of words of 5 letters formed by letters of the word BOMBAY.
[You should use only 5 letters out of 6 letters of the word BOMBAY]

solution given is ..................
.....
(1st case all the letters are different
total no. of words of this category = 5*4*3*2*1 = 120
2nd case B comes twice and 3 others
total no. of words of this category = 5*4*3*2*1/2*1 = 60
so total words = 120+60 = 180)

I think answer should be 360
as
solution should be

1st case all the letters are different
total no. of words of this category = 5*4*3*2*1 = 120
2nd case B comes twice and 3 others
total no. of words of this category = 4*(5*4*3*2*1/2*1) = 60*4=240 because there will be 4 combinations of such words.
so total words = 120+240 = 360

pls excuse me if I am wrong.

Asked In m4maths Aman (13 years ago)
Unsolved Read Solution (2)
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(#M40009906) M4MATHS QUESTION 9 balls Keep an EYE Keep an eye puzzle Keep an eye puzzle

You have nine balls, three of which are slightly heavier, and three of which are slightly lighter than the normal three. All three balls in each group has the same weight. All nine balls are identical otherwise. Your mission is to determine the group of every ball using a pair of scales.

How many weighings are needed in order to ensure the accomplishment of your mission?

Asked In m4maths Atul (13 years ago)
Unsolved Read Solution (2)
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(#M40008859) M4MATHS QUESTION powers Keep an EYE Keep an eye puzzle Keep an eye puzzle

what is the remainder when 223^224 is divisible by 25?

Asked In m4maths B.Senthil Kumar (13 years ago)
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(#M40008342) M4MATHS QUESTION power puzzle Keep an EYE Keep an eye puzzle Keep an eye puzzle

32=2^5 1024=2^10
2^(10+10+5)
64=2^6 128=2^7
2^(6+13+7)
+2^(18+4+3)

Asked In m4maths sivaraman (13 years ago)
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Maths Quotes

Black holes result from God dividing the universe by zero.

Unknown

The essence of mathematics is not to make simple things complicated, but to make complicated things simple.

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