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Frequently Asked TCS Placement Papers with Solution Page 915

(#M40000666) TCS QUESTION Keep an EYE

Alok and Bhanu play the following min-max game. Given the expression
N = 9 +X + Y - Z
where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be
option
a) 9
b) -18
c) 2
d) 20

Solution

First Read the question carefully, According to the given question all the numbers will be decided by alok and first 2 would be put by bhanu whereas alok will put the 3rd one.
So for getting maximum alok will tell 7 as the first Number
two cases arise
1) if bhanu will put this number as Z then 9, 9 will be the next 2 number. and 9+x+y-z = 20
2) if bhanu will put this number X, then alok will tell 4 or 5 as next number.
if bhanu will put 4 or 5 as Z then alok will put 9 as Y. So N will be
9+x+y-z= 9+7+9-4 = 21 OR 9+7+9-5 = 20

IF bhanu will put 4 or 5 as Y then alok will put 0 as Z
9+x+y-z = 9+7+4-0 = 20 OR 9+7+5-0 = 21

So if both are playing with there best effort then 9+x+y-z will be 20

20 is the correct answer

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Asked In TCS arun (14 years ago)

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(#M40000665) TCS QUESTION Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
option
(a) 1 hour
(b) 2 hours
(c) 3 hours
(d) 4 hours

Solution

suppose avg speed of aircraft is v km/hr,and it takes t hr to trip 600 km.
then t=600/v.......(1)
now avg speed slowed down by 200 km/hr and it takes 30 more minutes that means now it takes t+30/60=t+1/2 hr and speed is v-200
now time=distance/speed=>t+1/2=600/(v-200)
2t+1=1200/(v-200)
(2t+1)(v-200)=1200
(2t+1)((600/t)-200))=1200 from (1)
on solving it t= -3/2 or 1
time cant be -ve,hence answer is 1 hr.
This answer is given by MOHD ANAS and is correct answer

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Asked In TCS pradeep (14 years ago)

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(#M40000664) TCS QUESTION Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
option
(a) 1 hour
(b) 2 hours
(c) 3 hours
(d) 4 hours

Asked In TCS pradeep (14 years ago)

Solved Raushan Kumar Read Solution (3)

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(#M40000662) TCS QUESTION Keep an EYE

Anoop managed to draw seven circles of equal radii with their centers on the diagonal of a square such that two extreme circles touch two sides of the square & each middle circle touches two circles on the either side.Find the ratio of the circles to the sides of the square.
a)1:(2+7*sqrt(2))
b)1:(2+6*sqrt(2))
c)(2+7*sqrt(2)):1
d)1:(4+7*sqrt(3))

Asked In TCS pradeep (14 years ago)

Solved Asheesh Jain Read Solution (4)

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(#M40000614) TCS QUESTION Keep an EYE

Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?
option
(a) Rs. 22,781.25
(b) Rs. 24,150.25
(c) Rs. 28,140.50
(d) Rs. 18,000

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved mohd anas Read Solution (2)

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(#M40000626) TCS QUESTION Keep an EYE

7. Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?



(a) Rs. 22,781.25 (b) Rs. 24,150.25 (c) Rs. 28,140.50 (d) Rs. 18,000

Asked In TCS anuj (14 years ago)

Solved Pritam Kumar Paul Read Solution (1)

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(#M40000648) TCS QUESTION Keep an EYE

A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it
hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery?
option
a) 0.75
b) 1
c) 0.5
d) 0.25

Solution

Since according to requirement we have to locate Q closer to center in comparison to the circumference, for doing this we shall make a circle in that board whose radius will be half of the radius of dartboard.now we will compare the area of inner circle to the total area
Answer of DIPIN is correct
area of whole circle = pi*(1 foot)^2 = pi (this is according to formula area = pi*(radius)^2
similarly area of inner circle = pi*(1/2foot)^2 = pi/4
so ratio of areas of these two circles will be the probability and that is 1/4


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Asked In TCS Bhavani (14 years ago)

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(#M40000645) TCS QUESTION Keep an EYE

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
option
a) 1
b) 3
c) 4
d) 0

Solution

Answer will be (c)
There will be four points satisfying the given condition
one point will be incentre of the circle and other three will be excentres


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Asked In TCS (14 years ago)

Solved Read Solution (4)

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(#M40000605) TCS QUESTION Keep an EYE

1! + 2! +......... + 50!=?
a)3.1035*10^64
b)2.1021*10^65
c)3.1035*10^63
d)3.1035*10^62

Solution

solve 50! + 49! + 48!
others are lower terms
this can be done by calculator only

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Asked In TCS Sumandeep Ghosh (14 years ago)

Solved SANTOSH AGRASINGH Read Solution (2)

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(#M40000604) TCS QUESTION Keep an EYE

Given a collection of points P in the plane , a 1-set is a point in P that can be separated from the rest by a line, .i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e no three points in P lie on a line) is
a) 3
b) 5
c) 2
d) 8

Solution

The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3


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Asked In TCS Sumandeep Ghosh (14 years ago)

Solved Read Solution (5)

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