• Placement Questions
• /
• Tcs

tcs Placement Papers with Solution Page 900

(#M40000672) TCS QUESTION Keep an EYE

Lady has 2 select gloves & hat from a basket. In the dark, she can distinguish hat & gloves. 14 red, 20 blue, 18 green are there. Find probability that any selected glove pair has same color.

Asked In TCS arun (14 years ago)

Unsolved Read Solution (7)

Is this Puzzle helpful?   (14)   (6) Submit Your Solution Permutation and Combination

(#M40000671) TCS QUESTION Keep an EYE

A lady had fine gloves and hats. 25 blue, 7 red and 9 gey. She had to select a pair among them. But there was no light so she had to select in darkness the correct pair with a glove and a hat. Therefore how many combinations of same color she can select?

Asked In TCS arun (14 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (7)   (4) Submit Your Solution

(#M40000448) TCS QUESTION Keep an EYE

given a collection of points P in a plane,a 1-set is a point in P that can be separated from the rest by a line; i.e the point lies on one side of the line while others lie on other side. the no. of 1-set of P is denoted by n1(P). the maximum value of n1(P) over all configurations P of 10 points in the plane is?
a) 5
b) 3
c) 9
d) 10

Solution

The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3


Like manish sir answer on facebook.

Asked In TCS Manikanta (14 years ago)

Solved Read Solution (3)

Is this Puzzle helpful?   (33)   (5) Submit Your Solution Blood Relations

(#M40000669) TCS QUESTION Keep an EYE

A man has age in years equal to his daughters age in months and daughter age is equals to his grand daughter age in weeks and her age in weeks total age of 3 members is given 91.find out the mans age.

Asked In TCS arun (14 years ago)

Unsolved Read Solution (2)

Is this Puzzle helpful?   (8)   (0) Submit Your Solution Age Problem

(#M40000668) TCS QUESTION Keep an EYE

a man has age in years equal to his daughters age in months and
daughter age is equals to his grand daughter age in weeks and her age
in weeks total age of 3 members is given 91.find out the mans
age

Solution

let the age of man (in years) = x
age of daughter = x (in months) = x/12 years
age of grand daughter = x/12 (in weeks) = x/(12*52) years
now x + x/12 + x/(12*52) = 91
on solving we will get x = 83.876 years = 84 years (approx)
so age of man = 84, that of daughter = 84/12 = 7 years
and that of grand daughter = 7 weeks (approx 0 years)

Like manish sir answer on facebook.

Asked In TCS arun (14 years ago)

Solved Read Solution (2)

Is this Puzzle helpful?   (22)   (3) Submit Your Solution Age Problem

(#M40000667) TCS QUESTION Keep an EYE

The pace length P is the distance between the rear of two consecutive footprints. For men formula n/P = 144 gives approximate relationship between n and P where, n = number of steps per minute and P = pace length in meters. Bernard knows his pace length is 164cm. The formula applies to Bernard's walking. Calculate Bernard's walking speed in kmph.
a) 8.78
b) 236.16
c) 23.238
d) 11.39

Solution

n/P = 144 gives an approximate relationship between n and P where, n = number of steps per minute and P = pacelength in meters. Bernard knows his pacelength is 164cm.
Number of steps in one minute = 144*1.64
Distance travelled in 1 minute = 144*1.64*1.64 mtrs
Distance travelled in one hr = 144*1.64*1.64*60/1000 km = 23.24 km approx
This answer is given by DIPIN and is the correct answer


Like manish sir answer on facebook.

Asked In TCS arun (14 years ago)

Solved Bhavani Read Solution (4)

Is this Puzzle helpful?   (6)   (1) Submit Your Solution

(#M40000666) TCS QUESTION Keep an EYE

Alok and Bhanu play the following min-max game. Given the expression
N = 9 +X + Y - Z
where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be
option
a) 9
b) -18
c) 2
d) 20

Solution

First Read the question carefully, According to the given question all the numbers will be decided by alok and first 2 would be put by bhanu whereas alok will put the 3rd one.
So for getting maximum alok will tell 7 as the first Number
two cases arise
1) if bhanu will put this number as Z then 9, 9 will be the next 2 number. and 9+x+y-z = 20
2) if bhanu will put this number X, then alok will tell 4 or 5 as next number.
if bhanu will put 4 or 5 as Z then alok will put 9 as Y. So N will be
9+x+y-z= 9+7+9-4 = 21 OR 9+7+9-5 = 20

IF bhanu will put 4 or 5 as Y then alok will put 0 as Z
9+x+y-z = 9+7+4-0 = 20 OR 9+7+5-0 = 21

So if both are playing with there best effort then 9+x+y-z will be 20

20 is the correct answer

Like manish sir answer on facebook.

Asked In TCS arun (14 years ago)

Solved Read Solution (5)

Is this Puzzle helpful?   (9)   (4) Submit Your Solution

(#M40000665) TCS QUESTION Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
option
(a) 1 hour
(b) 2 hours
(c) 3 hours
(d) 4 hours

Solution

suppose avg speed of aircraft is v km/hr,and it takes t hr to trip 600 km.
then t=600/v.......(1)
now avg speed slowed down by 200 km/hr and it takes 30 more minutes that means now it takes t+30/60=t+1/2 hr and speed is v-200
now time=distance/speed=>t+1/2=600/(v-200)
2t+1=1200/(v-200)
(2t+1)(v-200)=1200
(2t+1)((600/t)-200))=1200 from (1)
on solving it t= -3/2 or 1
time cant be -ve,hence answer is 1 hr.
This answer is given by MOHD ANAS and is correct answer

Like manish sir answer on facebook.

Asked In TCS pradeep (14 years ago)

Solved Read Solution (1)

Is this Puzzle helpful?   (4)   (0) Submit Your Solution General Mental Ability

(#M40000664) TCS QUESTION Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
option
(a) 1 hour
(b) 2 hours
(c) 3 hours
(d) 4 hours

Asked In TCS pradeep (14 years ago)

Solved Raushan Kumar Read Solution (3)

Is this Puzzle helpful?   (4)   (1) Submit Your Solution

(#M40000663) TCS QUESTION Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
option
(a) 1 hour
(b) 2 hours
(c) 3 hours
(d) 4 hours

Solution

suppose avg speed of aircraft is v km/hr,and it takes t hr to trip 600 km.
then t=600/v.......(1)
now avg speed slowed down by 200 km/hr and it takes 30 more minutes that means now it takes t+30/60=t+1/2 hr and speed is v-200
now time=distance/speed=>t+1/2=600/(v-200)
2t+1=1200/(v-200)
(2t+1)(v-200)=1200
(2t+1)((600/t)-200))=1200 from (1)
on solving it t= -3/2 or 1
time cant be -ve,hence answer is 1 hr.
This answer is given by MOHD ANAS and is correct answer

Like manish sir answer on facebook.

Asked In TCS pradeep (14 years ago)

Solved Read Solution (1)

Is this Puzzle helpful?   (8)   (2) Submit Your Solution