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tcs Placement Papers with Solution Page 910

(#M40000454) TCS QUESTION Keep an EYE

Out of 7 children the youngest is boy then find the probability that all the remaining children are boys
a) 1/64
b) 1/32
c) 1/128
d) 1/256

Asked In TCS (14 years ago)

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(#M40000453) TCS QUESTION Keep an EYE

Susan made a block with small cubes of 8 cubic cm volume to make a block ,3 small cubes long, 9 small cubes wide and 5 small cubes deep. She realizes that she has used more small cubes than she really needed. She realized that she could have glued a fewer number of cubes together to lock like a block with same dimensions, if it were made hollow. What is the minimum number of cubes that she needs to make the block?
option
a) 114
b) 135
c) 21
d) 71

Asked In TCS (14 years ago)

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(#M40000452) TCS QUESTION probability Keep an EYE

A lady took out jacket and gloves, which are available in blue 26,yellow 30 and red 56. Power goes off, she can distinguish between gloves and jacket but not in colors. What is the possibility that she will pick up pair of gloves of each color?

Solution

(26c2 + 30c2 + 56c2)/112c2 = 235625/2589186 = 0.091
This answer is given by MUKESH RANJAN MALLICK and is correct answer

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Asked In TCS Karthik (14 years ago)

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(#M40000536) TCS QUESTION Keep an EYE

There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
A. P=1/3+(2/3*p^3) B. P=2/3+(2/3*p^3) C. P=2/3+(1/3*p^3) D P=2/3+(2/3*p^3)

Asked In TCS Karthik (14 years ago)

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(#M40000535) TCS QUESTION Keep an EYE

How many 13 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if repetition of digits is allowed?

Asked In TCS Karthik (14 years ago)

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(#M40000534) TCS QUESTION Keep an EYE

How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is not allowed?
a) 5^7
b) 5^6
c) 5^9
d) 5^8

Asked In TCS Karthik (14 years ago)

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(#M40000529) TCS QUESTION Keep an EYE

There is a die with 10 faces. It is not known that fair or not. 2 captains want to toss die for batting selection. What is the possible solution among the following?
a) If no. is odd it is head, if no. is even it is tail
b) If no. is odd it is tail, if no. is even it is head
c) Toss a die until all the 10 digits appear on top face. And if first no. in the sequence is odd then consider it as tail. If it is even consider it as head.

Asked In TCS (14 years ago)

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(#M40000455) TCS QUESTION Keep an EYE

Sangakara and Ponting selects batting by using a dice, but dice is biased. So to resolve, Ponting takes out a coin. What is the probability that coin shows correct option?
a) 1/2
b) 1/6
c) 1/12
d) 6/10

Asked In TCS (14 years ago)

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(#M40000447) TCS QUESTION Keep an EYE

Anoop managed to draw 7 circles of equal radii with their centres on the diagonal of a square such that the two extreme circles touch two sides of the square and each middle circle touches two circles on either side. Find the ratio of the radius of the circles to the side of the square

Solution

Let the radius of circle be r
let the side of square be a
then diagonal of square= a*sqrt(2)
This diagonal length = 12*r + 2r * sqrt(2)
(because the extreme circle's radius is perpendicular to side of square.)
Thus we get

12*r+2r*sqrt(2)=a*sqrt(2)

r(6*sqrt(2)+2)=a

r/a=1/(6*sqrt(2)+2)

Thus ratio: r:a = 1:(6*sqrt(2)+2)

Ans: 1:(6*sqrt(2)+2)
this answer is given by MUGIL VANNAN, and is right


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Asked In TCS raviteja (14 years ago)

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(#M40000446) TCS QUESTION Stacked Gold Coin Keep an EYE

Alice and Bob play the following coins-on-a-stack game. 20 coins are stacked one above the other. One of them is a special (gold) coin and the rest are ordinary coins. The goal is to bring the gold coin to the top by repeatedly moving the topmost coin to another position in the stack.


Alice starts and the players take turns. A turn consists of moving the coin on the top to a position i below the top coin (0 = i = 20). We will call this an i-move (thus a 0-move implies doing nothing). The proviso is that an i-move cannot be repeated; for example once a player makes a 2-move, on subsequent turns neither player can make a 2-move.


If the gold coin happens to be on top when it's a player's turn then the player wins the game.


Initially, the gold coinis the third coin from the top. Then
Alice has no winning strategy.
In order to win, Alice's first move should be a 1-move.
In order to win, Alice's first move can be a 0-move or a 1-move.
In order to win, Alice's first move should be a 0-move.

Asked In TCS Sathish (14 years ago)

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