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IBM Placement Papers with Solution Page 22

(#M40157069) IBM QUESTION Logical Keep an EYE

1) A person starts at 2.05PM with 40km/hr and reaches to 8.35 pm. then how much distance he travelled?

2) Company invests $0.33 raw,$4.92 manufacturing, #3.34 adv. if the comapany decided to sell the product $8.61. What is the net profit to get 50000 profit.

Asked In IBM induname (9 years ago)

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(#M40157068) IBM QUESTION Logical Keep an EYE

P software has coding line 5% more than N, N software has coding line 4/13 more than M. M software has 78 lines of coding. find P lines.

Asked In IBM induname (9 years ago)

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(#M40157037) IBM QUESTION Geometry Keep an EYE

In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED.

Asked In IBM Shubham sharma (9 years ago)

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(#M40157001) IBM QUESTION Keep an EYE

find missing number
-5 1 -11 23 29 17 -20 -14,?

Asked In IBM SHOUVICK DAS (9 years ago)

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(#M40156570) IBM QUESTION Post IPAT test....? Keep an EYE

Hey guys,

Has anyone taken the IPAT test recently for IBM? I just completed mine yesterday. How long typically until you get a reply from IBM (Canada)?? Does anyone know?

Thank you.

Asked In IBM EmK (9 years ago)

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(#M40156254) IBM QUESTION Keep an EYE

In the following questions select the number(s) from the given options for completing the given series.
Q.2 36,24,15,9,6? a) 3 b) 6 c) 0 d) 2
Q.3 98,72,14,? a) 8 b) 6 c) 4 d) 2
Q.4 69,55,26,13,? a) 3 b) 6.5 c)13 d) 4

Asked In IBM Prashant arora (9 years ago)

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(#M40155269) IBM QUESTION Keep an EYE

96 64 128 192 128 256 288 192

Asked In IBM Isabel Toro (9 years ago)

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(#M40155120) IBM QUESTION Keep an EYE

31,14,18,30,15,19

Asked In IBM pureiy (9 years ago)

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(#M40155065) IBM QUESTION help... Keep an EYE

plz tell is dere recruitment going on in bangalore for system engineer profile

Asked In IBM anku (9 years ago)

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(#M40154974) IBM QUESTION Keep an EYE

If the ratio of the roots of the equation x2 – 2ax + b = 0 is equal to that of the roots x2 – 2cx + d = 0, then:
a) a2b = c2 d b) a2c = b2d
b) a2d = c2b d) d2 b = c2 a

Asked In IBM neha (9 years ago)

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