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KVPY Exam Pattern, KVPY Questions with Answers Page 16

KVPY Select Another Category Select Another Topic

Government Jobs Exams

  • Bank Exam 478
  • CDS 57
  • CTET 21
  • IBPS 1258
  • IES EC 44
  • KVPY 364
  • NDA 481
  • NTSE 36
  • REVENUE OFFICE 53
  • RRB 1029
  • SSC 1294
  • UPSC 441

KVPY Question Topics

    Category (1)

    General Ability (1)

  • General Knowledge (1)
  • Logical Reasoning (3)

  • Blood Relations (1)
  • Mathematical Reasoning (1)
  • Number Series (1)
  • Verbal Ability (1)

  • Synonyms (1)
Keep an EYE (0)
Solved Question (0) UnSolved Question (365)
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(#M40027177) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

Extraction of silver is achieved by initial complexation of the ore (Argentite) with X followed by reduction
with Y. X and Y respectively are
(A) CN– and Zn (B) CN– and Cu (C) Cl– and Zn (D) Br– and Zn

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(#M40027176) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

The hybridizations of Ni(CO)4 and Cr(H2O)6
2+, respectively, are
(A) sp3 and d3sp2 (B) dsp2 and d2sp3 (C) sp3 and d2sp3 (D) dsp2 and sp3d2

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(#M40027175) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

The Quantum Hall Resistance RH is a fundamental constant with dimensions of resistance. If h is Planck's
constant and e the electron charge, then the dimension of RH is the same as -
(A) e^2/h (B) h/e^2 (C) h^2/e (D) e/h^2

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(#M40027174) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

The total radiative power emitted by spherical blackbody with radius R and temperature T is P. If the radius
if doubled and the temperature is halved then the radiative power will be -
(A) P/4 (B) P/2 (C) 2P (D) 4P

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(#M40027173) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

Due to transitions among its first three energy levels, hydrogenic atom emits radiation at three discrete
wavelengths λ1, λ2, and λ3 (λ1 < λ2 < λ3). Then -
(A) λ1 = λ2 + λ3 (B) λ1 + λ2 = λ3 (C) 1/λ1 + 1/λ2 = 1/λ3 (D) 1/λ1 = 1/λ2 + 1/λ3

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(#M40027172) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

An electron collides with a free molecules initially in its ground state. The collision leaves the molecules in
an excited state that is metastable and does not decay to the ground state by radiation. Let K be the sum of
the initial kinetic energies of the electron and the molecule, and P
r
the sum of their initial momenta. Let K'
and P' represent the same physical quantities after the collision. Then -
(A) K = K', P = P' (B) K' < K, P = P' (C) K = K', P ≠ P' (D) K' < K, P ≠ P'

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(#M40027171) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

In a Young's double slit set-up, light from a laser source falls on a pair of very narrow slits separated by 1.0
micrometer and bright fringes separated by 1.0 millimeter are observed on a distant screen. If the frequency
of the laser light is doubled, what will be the separation of the bright fringes ?
(A) 0.25 mm (B) 0.5 mm (C) 1.0 mm (D) 2.0 mm

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(#M40027170) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

At 23ºC, a pipe open at both ends resonates at a frequency of 450 hertz. At what frequency does the same
pipe resonate on a hot day when the speed of sound is 4 percent higher than it would be at 23ºC ?
(A) 446 Hz (B) 454 Hz (C) 468 Hz (D) 459 Hz

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(#M40027169) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

A plane polarized light passed through successive polarizers which are rotated by 30º with respect to each
other in the clockwise direction. Neglecting absorption by the polarizers and given that the first polarizer's
axis is parallel to the plane of polarization of the incident light, the intensity of light at the exit of the fifth
polarizer is closest to -
(A) same as that of the incident light (B) 17.5% of the incident light
(C) 30% of the incident light (D) zero

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(#M40027168) KVPY QUESTION General Ability Test Keep an EYE Keep an eye puzzle Keep an eye puzzle

A speaker emits a sound wave of frequency f0. When it moves towards a stationary observer with speed u,
the observer measures a frequency f1. If the speaker is stationary, and the observer moves towards it with
speed u, the measured frequency is f2. Then -
(A) f1 = f2 < f0 (B) f1 > f2 (C) f1 < f2 (D) f1 = f2 > f0

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