Latest TCS Aptitude Question SOLUTION: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then

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Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kegs of Apples is
a) 3.50 b) 10.53 c) 1.17 d)2.8

Asked In TCS krishnamurthy (11 years ago)

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nagarjun  (11 years ago)

30L+3Q=11.67
30L+6Q=12.48
------------
3Q=.81 Q= .27
from that L=0.362 cost of 10 kg apple is 10*.362=3.6

Is this solution Helpfull? Yes (81) | No (1)  

Yash Ajmera  (11 years ago)

Ans. 3.62

As 36 KG = Rs 12.48
-33 KG = Rs 11.67
----------------
3 KG = Rs o.81
----------------

So
33 KG = 11.67
-03 KG = 00.81
--------------
30 KG = 10.86
--------------

So 10 KG = 10.86/3 = 3.62

Is this solution Helpfull? Yes (13) | No (2)  

anitha  (11 years ago)

so is dat a dummy question...r can v mark 3.50 as it is nearer plz help

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shweta tiwari  (9 years ago)

30KG=RS L
33KG=RS 11.67
1KG=11.67/33=RS 0.353
10KG=0.353*10=RS 3.5

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neha upadhyay  (7 years ago)

30L+3Q=11.67
30L+6Q=12.48
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 0.362
Cost of 10 kgs of apples = 0.362 x 10 = 3.62

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Chunduru Nikhitha Prasanna  (4 years ago)

33=(30+3)
so the cost of 33kgs apples according to question is 30L+3Q=11.67 ---->eq(1)
36=(30+6)
so the cost of 36kg apples is 30L+6Q ---->eq(2)
by solving eq(1) and eq(2)
we get L=0.36 and Q=0.27
Lis cost of 1kg of apples then cost of 10kg =0.36*10=>3.6=>3.50(approx.)

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mohan raj  (5 years ago)

30L+3Q=11.67
30L+6Q=12.48

subtracting one from other
3Q=0.81
Q=0.81/3
Q=0.27
10*Q=2.7

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ni  (4 years ago)

30 kg price is 11.67
1kg price is 0.389
36 kg price is 12.48
1kg price is 0.346
10 kg price is 3.46(approx)
3.5 answers a

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