Latest TCS Aptitude Question SOLUTION: What is the remainder when the number 1234567.......424344 is divided by 45

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What is the remainder when the number 1234567.......424344 is divided by 45

Asked In TCS Subrata Sarkar (11 years ago)

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Shashank Mishra  (11 years ago)

remainder will =9
write number as (1234.............4142290+54)%45
12345...............4142290 fully divisible by 45 as
bcoz sum is ((44*45)/2-54)=936 which is divisible by 9
and last digit is 0 hence also divisible by 5
so just concern about 54
hence 54%45=9 is answer

Is this solution Helpfull? Yes (21) | No (1)  

Reema khan  (11 years ago)

for number to be divisible by 45 it should be divisible by both 5 and 9 to chk the divisiblity by 9 find the sum of the digits
1-9=45+1(of 10)=46
11-20=9+45+2=56
21-30=18+45+3=66
31-40=27+45+4=76
41-44=16+10=26
so sum of digits=270
270 is divisible by 9
since 5 and 9 are co-prime numbers...the number given number should also be divible by 5...on dividing the number by 5 we get a remainder of 4
so ans is 4.

Is this solution Helpfull? Yes (9) | No (7)  

Reema khan  (11 years ago)

sorry dres a mistake ans will be 9..!!!

Is this solution Helpfull? Yes (4) | No (1)  

darshan tumballi  (11 years ago)

factors of 45 are 9 n 5.
it is simple divisible by 9
(clearly ie add all nos (1+44)*44/2)
has reminder as 4 divided by 5..
so continiously subtract 9 untill u can make it divisible by 5..
which is 9*1(one time)..
so reminder is 9.

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SHANU MAHAJAN  (11 years ago)

ans is 0 as sum of this series is 990 and i6t is completely divisible by 45

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karpagam  (11 years ago)

the last digit of remainder will be 9

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niki  (11 years ago)

please explain how..?

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semanti dey  (11 years ago)

pls explain..cant undrstand...

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jaya  (11 years ago)

plz @reema xplain how u add the no's divisble by 9.
41-44=16+10??...

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