Latest TCS Aptitude Question SOLUTION: What is the remainder when 100!/97^2.

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(#M40012005) TCS question Keep an EYE

What is the remainder when 100!/97^2.

Asked In TCS Ashish Singh (11 years ago)

Unsolved Read Solution (8)

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sharmi mukherjee  (11 years ago)

the ans is 8827

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RAHUL KUMAR  (11 years ago)

8827 IS CORRECT

Is this solution Helpfull? Yes (4) | No (3)  

deepak srivastava  (11 years ago)

100!/97^2=100*99*98*97*96!
Now According to WILSON's Theorem
(n-1)!/n gives remainder -1
so,by applying it we have
(96!*97*98*99*100)/97*97 = (96!*98*99*100)/97
96!/97 gives remainder as -1
And 98/97 gives rem. as 1
sly,99 And 100 divided by 97 gives rem. as 2 and 3 respectvly,
now total rem. is -1*1*2*3 = -6
so rem. is 97-6 = 91
remainder of the question is 91*97=8827
ANS; 8827
(we multiplied 91 by 97 because in previous steps we have divided by 97).

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snehil  (11 years ago)

6 will be the remainder

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swarup  (11 years ago)

sharmi plz explain the answer

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Rahul singh  (11 years ago)

i think it will solved using wilson's therom.

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niki  (11 years ago)

please some1submit a proper solution.

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Ashish Singh  (11 years ago)

what is wilson's therom?

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