Latest TCS Aptitude Question SOLUTION: if P(x)= ax^4 + bx^3 + cx^2 + dx + e has roots x= 1,2,3 and 4 and P(0) = 48, what is P(5)? #48 #24 #0 #50

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if P(x)= ax^4 + bx^3 + cx^2 + dx + e has roots x= 1,2,3 and 4 and P(0) = 48, what is P(5)?

#48
#24
#0
#50

Asked In TCS Nishant Sanghai (12 years ago)

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nik  (12 years ago)

ans is 48....
x-1,x-2,x-3 ,x-4 are factors of p(x)

p(x) = k(x-1)(x-2)(x-3)(x-4) , where k is a constant

but given p(0) =48

24*k =48
k=2
p(x) =2(x-1)(x-2)(x-3)(x-4)
p(5)= 2*4*3*2*1 = 48

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richa gupta  (12 years ago)

answer a) 48

if 1 is a root then x-1 is a factor of p(x)
similarly x-2 is a factor,x-3 ,x-4 are factors

but p(x) is 4th degree polynomial therefore it can be in the form

p(x) = k(x-1)(x-2)(x-3)(x-4) , where k is a constant

but given p(0) =48

therefore 24 k =48

k=2

p(x) =2(x-1)(x-2)(x-3)(x-4)

p(5)= 2*4*3*2*1 = 48

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ajay  (12 years ago)

ans is 48

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RAHUL KUMAR  (12 years ago)

ans. 48

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Sankhadeep  (12 years ago)

well think logically..........p(0)=48.....so as given epression p(x)=much much greater for x=1,2,3,4 pr 5.....look at the options....24,0 is nt possible as they r smaller than 48.....50is nt possible after looking at the expresion.....so only 48 is possible....we have to consider a=b=c=d=0 , only value of e=

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