Latest TCS Aptitude Question SOLUTION: 10lts of water were added to ten lts of a 30% strong solution of sulphuric acid.what is the strength of resulting solution?

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10lts of water were added to ten lts of a 30% strong solution of sulphuric acid.what is the strength of resulting solution?

Asked In TCS charan (11 years ago)

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yeginati haribabu  (11 years ago)

In ten ltr solution,the quantity of sulphuric acid = .3*10=3lts
now solution contain = 7+10 ltr water = 17ltr and 3lts of acid
total solution =20lts
soltuion is = 3/20 *100 = 15%

Is this solution Helpfull? Yes (32) | No (2)  

mohd zubair khan  (11 years ago)

sulphuric acid=SA and water=W
so ratio in initial mixture SA:W=30:70
so sulphuric acid =3 ltr and water= 7 ltr
now in final mixture acid=3 ltr and water= 17 ltr
ratio SA:W=3:17
now strength={3/(3+17)}*100
=15%
(ANSWER)

Is this solution Helpfull? Yes (20) | No   

Piyush Jain  (11 years ago)

In ten ltr solution,the quantity of sulphuric acid = .3*10=3lts
now solution contain = 7+10 ltr water = 17ltr
soltuion is = 3/17 *100 = 17.647%

Is this solution Helpfull? Yes (2) | No (14)  

arti   (11 years ago)

quantity of sulphuric acid =30/100*10=3 lt
now solution has 7 +10=17 lt water
total solutin=20 lt
strength =3/20*100=15%

Is this solution Helpfull? Yes (1) | No   

lakshmi reddy  (11 years ago)

10 ltrs of 30% strong solution of suslphuric acid has (30/100)*10=3 ltrs of water...when 10 ltrs of water is added to this solution,amount of water in resultant solution is 13 ltrs.so strength of solution is x....(x/100)*10=13=>x=130...strength of resultant solution is 130%

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