Latest TCS Aptitude Question SOLUTION: 1 t0 44 like 1234567891011121314151617181920......424344 what is remainder whn divided by 45??

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1 t0 44 like 1234567891011121314151617181920......424344
what is remainder whn divided by 45??

Asked In TCS Hassan (11 years ago)

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subhash dhaka  (11 years ago)

Ans is 4
division by 45 means division by 9 and 5(9*5)
for divsion by 5 ,last digit either should be 0 or 5
and by 9 ,sum of digit should be divided by 9.
as there is no remainder when division by 9.but on division by 5 ,4 is remainder.
so answer is 4.

Is this solution Helpfull? Yes (32) | No (23)  

SANCHIT GOEL  (8 years ago)

Let N = 1234567891011121314151617181920......424344

Remainder when N is divided by 5 is 4.  So N = 5K + 4 .....(1)

Remainder when N is divided by 9 is Sum of the digits of N divided by 9. We know that

1+2+3+...44 = 990 Which gives digit sum as 9. So remainder when N is divided by 9 is 0.

So N = 9L .....(2)

Equation (1) and (2) we 9L = 5K + 4

For K = 1 this equation gets satisfied. So least possible number satisfies the condition is 9

So The general format of N = w(LCM of (9, 5)) + Least number satisfies the condition.

So N = w.45 + 9

When N is divided by 45, we get 9 as remainder.

Is this solution Helpfull? Yes (9) | No (3)  

K.Shyam Prasad Rao  (11 years ago)

sum of n natural no is=n*n+1/2,so n=44,44*45/2=22*45=990den 990/45 den rem is 0

Is this solution Helpfull? Yes (7) | No (27)  

sateesh vadlamuri  (11 years ago)

rem=9
2511/45=36
1314/45=9--------------36/4
1224/45=9---------------36/4

Is this solution Helpfull? Yes (7) | No (7)  

preetham   (8 years ago)

Let N = 1234567891011121314151617181920......424344
Remainder when N is divided by 5 is 4.  So N = 5K + 4 .....(1)
Remainder when N is divided by 9 is Sum of the digits of N divided by 9. We know that 1+2+3+...44 = 990 Which gives digit sum as 9. So remainder when N is divided by 9 is 0.
So N = 9L .....(2)
Equation (1) and (2) we 9L = 5K + 4
For K = 1 this equation gets satisfied. So least possible number satisfies the condition is 9
So The general format of N = w(LCM of (9, 5)) + Least number satisfies the condition.
So N = w.45 + 9
When N is divided by 45, we get 9 as remainder.

Is this solution Helpfull? Yes (1) | No (2)  

shubham  (8 years ago)

N = w(LCM of (9, 5)) + least.......need explanation, please help

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