Latest Others Aptitude Question SOLUTION: Two dices are thrown. What is the probality that the the number on the first dice is greater or equal to number on the second dice?

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Two dices are thrown. What is the probality that the the number on the first dice is greater or equal to number on the second dice?

Asked In Others Parijat Mukherjee (11 years ago)

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Garima  (11 years ago)

If first number is 6, then the probality that the the number on the first dice is greater or equal to number on the second dice = 1/6 *6/6 = 6/36=1/6
If first number is 5, then the probality that the the number on the first dice is greater or equal to number on the second dice = 1/6 * 5/6 = 5/36
If first number is 4, then the probality that the the number on the first dice is greater or equal to number on the second dice = 1/6 *4/6=4/36
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considering all cases, the probality that the the number on the first dice is greater or equal to number on the second dice = 6/36 +5/36 +4/36 +..+1/36 =
(1+2+3+4+5+6)/36 = 21/36 = 7/12

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Devendra Marghade  (11 years ago)

Total outcomes will be 6*6=36 like (1,1)(1,2),......,(6,6)
Out of that total possible conditions=21 like(1,1)(2,1)(2,2)(3,1)(3,2)(3,3)(4,1)(4,2)(4,3)(4,4)(5,1)(5,2)(5,3)(5,4)(5,5)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Therefore Probability=21/36=7/12

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geeta  (11 years ago)

1/6*1/6+1/6*2/6+1/6*3/6+1/6*4/6+1/6*5/6+1/6*6/6=7/12.........in every multiplication term 1/6 stands for probability of getting 1,2,3,4,5,6 on 1st die respectively and 2nd term for getting ......ex.if we get 3 on 1st die then we can have 1,2,3 on 2nd die thus 1/6*3/6....similarly for all cases

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