Latest exam Aptitude Question SOLUTION: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9

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(#M40144853) EXAM Numerical Ability question Keep an EYE

How do you solve for each variable:
(x-3)(x-7)=0
b^2+3b-4=0
n^2+n-12=0
5x^2+18x=8
3a^2+4a=2a^2-2a-9

Asked In exam (9 years ago)

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