Latest IBPS Aptitude Question SOLUTION: 80 coins are placed in a straight line on the ground. The distance between any 2 consecutive coins is 10 feet. How far must a person travel to bring them one by one to a basket pla

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(#M40152175) IBPS Numerical Ability question Keep an EYE

80 coins are placed in a straight line on the ground. The distance between any 2 consecutive coins is 10 feet. How far must a person travel to bring them one by one to a basket placed 10 feet behind the first coin?
a)64800
b)68400
c)86400
d)46800
e)48600

Asked In IBPS swathi (8 years ago)

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SruthiSahini  (8 years ago)

a)64800
Explanation:
Basket is 10 feet behind first coin.To take first coin a person has to travel 20ft(10+10) to and fro.Similarly,to collect second coin he has to travel 40ft (20+20) to & fro.This forms an A.P series.T0 collect last coin he has to travel 1600ft(800+800)

(10+10)+(20+20)+..............+(800+800)
=20+40+60+80+......+1600

Sum of n terns in A.P is n(a1+an)/2.

hence Sum of first 80 terms =80(20+1600)/2
=64800

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Tanushree Bhandary  (8 years ago)

to take first coin we need 10 feet then second coin (10+10)=20.......
10+20+30+...................+(80*10)
=80/2(2*10+(80-1)*10)
=32400ft

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