Latest CAT Aptitude Question SOLUTION: IF x, y and z can only take values 1,2,3,4,5,6 and 7. Then find the number of possible solutions of the equation x +y +z =12.

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(#M40152215) CAT Numerical Ability question Solution of equation (P and C) Keep an EYE

IF x, y and z can only take values 1,2,3,4,5,6 and 7. Then find the number of possible solutions of the equation x +y +z =12.

Asked In CAT (8 years ago)

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Devendra Marghade  (8 years ago)

37 solutions

If repetition of numbers is allowed, then possible solutions with x+y+z=12 are
(1,4,7) (1,5,6) (1,6,5) (1,7,4)
(2,3,5) (2,4,6) (2,5,5) (2,6,4) (2,7,3)
(3,2,7) (3,3,6) (3,4,5) (3,5,4) (3,6,3) (3,7,2)
(4,1,7) (4,2,6) (4,3,5) (4,4,4) (4,5,3) (4,6,2) (4,7,1)
(5,1,6) (5,2,5) (5,3,4) (5,4,3) (5,5,2) (5,6,1)
(6,1,5) (6,2,4) (6,3,3) (6,4,2) (6,5,1)
(7,1,4) (7,2,3) (7,3,2) (7,4,1)
=Total 37

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Devendra Marghade  (8 years ago)

In second row, pl. read first solution as (2,3,7) instead of (2,3,5).

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