Latest CAT Aptitude Question SOLUTION: a precious stone worth rupees 10872 fell and broke into three pieces, the weights of which are proportional to 1:2:3. the value of each stone is directly proportional to the square

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(#M40152338) CAT Numerical Ability question Keep an EYE

a precious stone worth rupees 10872 fell and broke into three pieces, the weights of which are proportional to 1:2:3. the value of each stone is directly proportional to the square of it weight. find the loss in the value caused by the breakage?

Asked In CAT manusmriti (8 years ago)

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Devendra Marghade  (8 years ago)

6644 Rs.

Let the weight of original stone=x, so x^2=10872, x=Sqrt(10872)
Weights of three pieces (in proportional to 1:2:3) will be Sqrt(10872)/6 , Sqrt(10872)*2/6 and Sqrt(10872)*3/6 respectively
So their values will be [Sqrt(10872)/6]^2 , [Sqrt(10872)*2/6]^2 and [Sqrt(10872)*3/6]^2 respectively
Sum of new values=(10872/36)+(10872*4/36)+(10872*9/36)=10872*14/36=4228
Loss in value=10872-4228=6644

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Adu  (8 years ago)

36x^2=10872 x^2= 302 after breaking total price = 14x^2=14*302, loss =6644

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