Latest HCL Aptitude Question SOLUTION: The number 642 is added to a 3-digit number 7x2 to give a 4 digit 13y4 which is exactly divisible by 11.find xy

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(#M40152973) HCL question Number Keep an EYE

The number 642 is added to a 3-digit number 7x2 to give a 4 digit 13y4 which is exactly divisible by 11.find xy

Asked In HCL ABHIRUCHI SHARMA (9 years ago)

Unsolved Read Solution (22)

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Read Solution (22) :

selvi  (9 years ago)

if a number is divisible by 11,means diff b/w it's digits at odd and even place should be 0 or multiples of 11.
so 13y4 1+y=3+4 y=6 therefore no is 1364
now subtract 642 from 1364=722
therefore x=2
xy=12

Is this solution Helpfull? Yes (27) | No   

Rupen Raj  (9 years ago)

xy=26......a no is divisible by 11 only when the diff btwn sum of digits at even place nd sum of digits at odd place is equal to zero or div by 11.......so..(1+y)-7=0.y=6.......thereaftr x will be 2....

Is this solution Helpfull? Yes (12) | No (5)  

priyamvada  (8 years ago)

642
7x2
--------
13y4


13y4 is divisible by 11
any number divisile by 11 if difference between sum of its digits at odd places and even places is either 0 or a number divisible by 11
so 3+4=7,1+y=7
y=6 x=2

Is this solution Helpfull? Yes (5) | No   

kishor kumar sahu  (9 years ago)

if a number is divisible by 11. when the diff b/w unit place and ten's place is equal to 0.so 13y4 (4+3)-(1+y)=0 then y=6 therefor no is 1364. now 1364-642=722.
therefor x=2 and y=6. xy=2*6=12.

Is this solution Helpfull? Yes (3) | No (1)  

ramakrishna  (9 years ago)

642+7x2=13y4
y=6=>1364
x=2
x*y=12

Is this solution Helpfull? Yes (2) | No (1)  

shekhar  (8 years ago)

x=2 y=6
xy=12

Is this solution Helpfull? Yes (1) | No   

gyan  (8 years ago)

1+y=3+4, than y=6 and x=2, so xy=12

Is this solution Helpfull? Yes (1) | No   

Obaid Alam  (9 years ago)

As 13y4 is divisible by 11,
so,
(4+3)-(y+1)=0
y=8

and now,
1384-642=742
Therefore,X=4,Y=8

Is this solution Helpfull? Yes | No (8)  

sowmyashree.k  (9 years ago)

1364,x=6,y=6,try to 11 divisible number by looking at last digit and 1st 2digits

Is this solution Helpfull? Yes | No   

Ankit kumar tripathi  (9 years ago)

13y4 must be divisible by 11 so (4+3)-(y+1)=?.and ? must be multiple of 11 or 0.in given number never possible to be 11 multiple so it should be 0. so y=6 then easily calculate the x=2.
SO THE ANSWER WILL BE 26

Is this solution Helpfull? Yes | No   

Saumya Bhasin  (9 years ago)

x=2, y=6; 13y4 is a no divisible by 11 so y=6((3+4+(1+6))=0 642+7x2=1364 so x=2;

Is this solution Helpfull? Yes | No   

Mal reddy  (8 years ago)

Ans:12min
54*t=45*(t+s)
s/t=1/5
s=t/5
per hr :s=60/5
s=12min

Is this solution Helpfull? Yes | No   

aditi ojha  (8 years ago)

13y4 is divisible by 11 so y = 6 and 642+7x2 = 1364
X=2

Is this solution Helpfull? Yes | No   

anjali mehta  (8 years ago)

, if a number is divisible by 11,means diff b/w it's digits at odd and even place should be 0 or multiples of 11.
(1+y)-(3+4)=0
so, y=6
subtract 642 from 1364=722
xy=12

Is this solution Helpfull? Yes | No   

Arpita Mehrotra  (8 years ago)

13y4/11=124 i.e. y=6 and when putting dis value in 642+7x2=1364 we will get x=2
therefore xy=12

Is this solution Helpfull? Yes | No   

kakumanu Gowthami  (8 years ago)

642+7x2=13y4
take x=2, y=6
then answer is 1364/11 is exactly divisible

Is this solution Helpfull? Yes | No   

santhoshi  (8 years ago)

x=2 y=6 because 13y4 is exactly divisible by 11 so the difference between sum of odd places and sum of even place must be 0 so (3+4)-(1+y) so y is 6 and x is 2

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sailakshmi  (8 years ago)

642+7x2=13y4
13y4 by trying to divide this with 11 it will be 124
from this we came to know that y=6
and for x since it is in the tenth place digit in the tenth place in the 642 is 4
then from 642+7x2=13y4
4+x=y;
4+x=6;
x=2;
then xy=12

Is this solution Helpfull? Yes | No (1)  

manohar  (8 years ago)

x=2,y=6 xy=12
11 is exactly divisible by 1364

Is this solution Helpfull? Yes | No   

akbarmuddasir  (8 years ago)

If a number is divisible by 11, means difference between its digits at odd and even place should be 0 or multiples of 11.
So, for 13y4 to be divisible by 11, 1+y should be equal to 3 + 4 i.e.
=> 1+y=3+4
=> y=6
Therefore no is 1364
Now subtract 642 from 1364=722
Therefore x=2
Hence, xy=12.

Is this solution Helpfull? Yes | No   

Madhullapalli Suhasini  (7 years ago)

For divisible of 11 (sum of odd places)-(sum of even places) 13y4 (1+y)-(3+4)=0 y=6 So x=2 from above given form so answer will be xy=6×2=12

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Divya Batra  (7 years ago)

answer is x=2 and y=6.
solution is:-
642+7x2=13y4
starting from x=1, we get y=5 and number 1354 is not divisible by 11.
then checked for x=2 and 1264 number is divisible by 11, so answer is xy=2*6=12

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