Latest IBPS Aptitude Question SOLUTION: A man purchased two cows for Rs 500. He sells the first at 12% loss and second at 8% gain. In this he neither gains nor loses. Find the selling price of the first cow? A. Rs 156 B

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(#M40154012) IBPS Numerical Ability question quant Keep an EYE

A man purchased two cows for Rs 500. He sells the first at 12% loss and second at 8% gain. In this he neither gains nor loses. Find the selling price of the first cow?
A. Rs 156
B. Rs 170
C. Rs 176
D. Rs 200

Asked In IBPS Sarabeshwar (8 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

MEET  (8 years ago)

CP of cows = 100x+100y=500
SP of cows = 88x+108y =500
so 100x+100y = 88x+108y
12x = 8 y
3x = 2 y -(1)
x+y = 500 -(2)
solving these give x=200 y=300
so SP of first will be 88% of 200 ie 176

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ravi  (8 years ago)

Suppose, first cow was purchased for rs = x,
then second cow was purchased for rs = 500-x, (since both were purchased in rs 500)

Since,
there is no profit no loss condition, so

Selling prize of both cows = Purchasing prize

selling prize of first cow at 12% loss + selling prize of second cow at 8% profit = purchasing prize

(x-12x/100) + [ (500-x) + (500-x)8/100 ] = 500

solving the equation you will get x=200

so selling prize = 200 - 12% loss on 200
= 200 - 12*200/100
= 176

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Dileepreddy  (6 years ago)

a+b=500
12%loss=8%gain
12a=8b => b=12a/8 => 3a/2

substitute b in above equation

a+3a/2=500 => a=200 cost price of first cow , b=300 cost price of second cow

selling price of first cow= 0.88a=> 200*0.88 => 176
selling price of secondcow= 1.08a=> 300*1.08 => 324

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