Latest Elitmus Aptitude Question SOLUTION: how many 3 digit numbers can be formed such that their sum should be 16. a. 60 b. 63 c. 66 d. none of the options i wrote 66 is it correct?

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(#M40154997) ELITMUS Category question number system Keep an EYE

how many 3 digit numbers can be formed such that their sum should be 16.

a. 60 b. 63 c. 66 d. none of the options

i wrote 66 is it correct?

Asked In Elitmus Bushra (8 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

NAVEEN KUMAR  (8 years ago)

ur ans is absolutely correct...

for soln deatails url " http://postimg.org/image/ls3nqwsj1/ "

Is this solution Helpfull? Yes (11) | No   

NAVEEN KUMAR  (8 years ago)

@abhishek. 907,970,709,790

Is this solution Helpfull? Yes (4) | No   

Arjun Kumar  (8 years ago)

Ans is 66.

addition of three no form 100 to 999

first start

907 in 4 ways.
916 in 6 ways.
925 in 6 ways.
934 in 6 ways.
total= 22

so on

808 in 2 ways.
817 in 6 ways.
826 in 6 ways.
835 in 6 ways.
844 in 3 ways.
total= 23.

so on
709 & 718 are not consider because we already consider above.
727 in 3 ways.
736 in 6 ways.
745 in 6 ways.
total = 15

and
664 in 3 ways.

565 in 3 ways.

so total no = 22+23+15+3+3=66

Is this solution Helpfull? Yes (3) | No   

jinit bansod  (8 years ago)

its answer is 60.

Is this solution Helpfull? Yes (1) | No (4)  

manish  (8 years ago)

I cant understand ur solution ,which is explaining in this: http://postimg.org/image/ls3nqwsj1/
Mr. Naveen Kumar

Is this solution Helpfull? Yes (1) | No   

priyanka  (8 years ago)

Why are you not considering 169 and few other numbers also.. i got total of 90 numbers.

Is this solution Helpfull? Yes (1) | No   

Yamini Kant Mahato  (8 years ago)

option D is the correct ans.

Is this solution Helpfull? Yes (1) | No   

Bushra  (8 years ago)

oh thank god..

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Abhishek gupta  (8 years ago)

plz explain ur ans in detail as how 907 = 4

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Pallavi  (8 years ago)

plzz can anybody post cryptography question of yesterday please????

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Aisha  (8 years ago)

www.javacodepoint.com

//What will be the O/P ?

class U
{
public static void main(String args[])
{
int i = 0;
int j = i++ + i + i-- + i + --i + i + ++i + i;
System.out.println(i);
System.out.println(j);
}
}

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NAVEEN KUMAR  (8 years ago)

@ Aisa
o/p-->0
0 for slon details url---> " http://postimg.org/image/4o89jibq7/ "

Is this solution Helpfull? Yes | No (2)  

PRASHANT  (8 years ago)

CAN YOU PLZ EXPLAIN THE SOLN.

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