Latest I GATE Aptitude Question SOLUTION: A, B and C can do a piece of work in 15 days. After all the three worked for 2 days, A left. B and C worked for 10 more days and B left. C worked for another 40 days and completed

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(#M40155101) I GATE Numerical Ability question time and work Keep an EYE

A, B and C can do a piece of work in 15 days. After all the three worked for 2 days, A left. B and C worked for 10 more days and B left. C worked for another 40 days and completed the work. In how many days can A alone complete the work if C can complete it in 75 days?

Asked In I GATE sumit paliwal (9 years ago)

Solved Devendra Marghade Read Solution (2)

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Devendra Marghade  (9 years ago) Best Solution

30 days

(1/A)+(1/B)+(1/C)=1/15 ----(i)
so A, B & C's 2 day work=2/15
10 days work of B & C= (10/B)+(10/C)
Remaining work is done by 'C' in 40 days=40/75=8/15
As (A,B & C's 2 days work)+(B & C's 10 days work)+(C's 40 days work)=complete work
So (2/15)+[(10/B)+(10/C)]+8/15=1 ----(ii)
Substituting 1/C=1/75 in (ii) and solving 1/B=1/50
Substituting values of 1/B & 1/C in (i), we get 1/A=1/30
So 'A' alone can complete the work in 30 days.

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samatha  (9 years ago)

why should substitute in middle 1/c=1/75 in the problem it is not given before the last statement

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