Latest C Aptitude Question SOLUTION: write a logic for following series 2,6,15,35,143,221,323,437,..........

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(#M40156460) C Programming question series Keep an EYE

write a logic for following series 2,6,15,35,143,221,323,437,..........

Asked In C bharat kumar (7 years ago)

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CH PADMA PRIYA  (7 years ago)

the sequence comprises of products of consecutive prime numbers
2=1*2
6=2*3
15=3*5
35=5*7
there should be a number in this series 77=7*11 (i dont know y this number is missing, otherwise my logic stands true)
143=11*13
221=13*17
323=17*19 and so on...
the logic is
for(int i=0;i

Is this solution Helpfull? Yes (20) | No (2)  

keshav patidar  (6 years ago)

#include

int main() {
int count=0;
int j;
int a;
int b;
int limit=15; //change how many no. you want to print
int prime(int n)
{
int flag=0;
int i;
if(n==2)
{flag=1;
a=2;}
else
for(i=2;i

Is this solution Helpfull? Yes (2) | No (2)  

Priyadharshini T  (7 years ago)

I dont know whether my logic is correct or not. i cant bring the logic in several steps
1*2=2
3*2=6
8*2=16-1=15
72*2=144-1=143
111*2=222-1=221
219*2=438-1=437
Please tell me the correct sequence

Is this solution Helpfull? Yes | No (5)  

trilok chand saini  (7 years ago)

the sequence comprises of products of consecutive prime numbers
2=1*2
6=2*3
15=3*5
35=5*7

Is this solution Helpfull? Yes | No (2)  

Akanksha Choubey  (6 years ago)

num= prime+num*2;

num starting from 2 and prime number starting from 2
num=2*2+2=6
num=6*2+3=15
num=15*2+5=35
num=35*2+7=77 and so on....

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Charulatha.G  (1 year ago)

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667
ANS: 667

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