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Java interview questions and answers for freshers

(#M40166286) JAVA QUESTION NEAREST PERFECT SQUARE Keep an EYE

Find the nearest perfect square of the given number.
Sample input:600
Sample output:576.

Sample input:47011
Sample output:47089

Asked In Java Arun (21 Days ago)

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(#M40166061) JAVA QUESTION efficient means of execution Keep an EYE

Which checks the object code to determine whether there are more efficient means of execution?
1)Interpreter
2) Linker
3)Compiler
4) Optimizer

Asked In Java Mehul KOTHARI (6 Months ago)

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(#M40165443) JAVA QUESTION Circles and distance Keep an EYE

Circles and Distances
Problem Description
Task is to calculate the straight line distance between the two objects moving in a circular path. They may move at different velocities. The distance has to be calculated after N seconds.

The figure and commentary below it, explains the problem in detail.

com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@491cde5b:image1.png

We have two point objects B and C at rest on a straight line at a distance r1 and r2 units from a point A. At time t=0 seconds, the objects start moving in a circular path with A at the center with velocity v1 and v2 degrees per second.

Given inputs v1, v2, r1 and r2, calculate the distance between the B and C after N seconds.

Distance should be printed up to an accuracy of 2 places after the decimal point. Use Rounding Half-up semantics.

Input Format
First line contains velocity of object B in degrees per second (v1)

Second line contains distance of object B from A (r1)

Third line contains velocity of object C in degrees per second (v2)

Fourth line contains distance of object C from A (r2)

Fifth line contains time in seconds after which the distance between B and C, is to be measured (N)

Output
The distance between B and C, N seconds after they are set in motion

Constraints

v1, v2, r1, r2 > 0 and all are integer values.

r2 > r1

0 < n <= 100

The objects move in anticlockwise direction

v1, v2 <=360

r2 <= 100


Explanation
Example 1

Input

90

5

270

10

1

Output

15.00

Explanation

After 1 second, the object at B would cover 90 degrees and the object at C would cover 270 degrees. Both the objects would be vertically opposite to each other and would lie in a straight line.

So the distance between them would be equal to the sum of their distance from the origin A=5+10= 15

Asked In Java joshika (1 year ago)

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(#M40165431) JAVA QUESTION string Keep an EYE

function of array

Asked In Java karthi (1 year ago)

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(#M40159591) JAVA QUESTION string Keep an EYE

how to replace , in a given string without using predefined methods

Asked In Java Ramya Krishna T (2 years ago)

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(#M40158275) JAVA QUESTION Keep an EYE

write a java programof string ; first letter should be upper case and rest in lowecase

Asked In Java div (2 years ago)

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(#M40157238) JAVA QUESTION Dinfference Keep an EYE

Distinguish class and object?

Asked In Java Surendra Naraga (3 years ago)

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(#M40157044) JAVA QUESTION technical Keep an EYE

A Chess board position is accurately captured by Forsyth-Edwards notation and is abbreviated as FEN. A FEN "record" defines a particular game position, all in one text line and using only the ASCII character set. A FEN record contains six fields. A complete description of the FEN format to represent Chess positions can be found at here

For the purpose of this problem only consider first of the six fields of FEN. Before we describe the problem, let us look at how FEN maps to a board position. The following 5 images show board positions and its corresponding FEN representation.


Figure 1.

Asked In Java satheesh (3 years ago)

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(#M40156335) JAVA QUESTION Any Keep an EYE

whether java is purely object oriented ?

Asked In Java Balaji S (3 years ago)

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(#M40156025) JAVA QUESTION java Keep an EYE

how can we print a statement in java with out main method in the java 7 version

Asked In Java PRABHANJAN (3 years ago)

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