Latest Elitmus Aptitude Question SOLUTION: a ,b and c can do a piece of work in 30,20 and 10 days respt.a is assisted by b on one day and by c on the other day alternately.how long would it take to finish the work?

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(#M40164069) ELITMUS Numerical Ability question Keep an EYE

a ,b and c can do a piece of work in 30,20 and 10 days respt.a is assisted by b on one day and by c on the other day alternately.how long would it take to finish the work?

Asked In Elitmus Sniper (7 years ago)

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piyush yadav  (7 years ago)

a can do 2 units of total work in a day
b can do 3 units of total work in a day
c can do 6 units of total work in a day

and so when a and b will work together, they will complete 5 units of total work in a day
while a and c working together, perform 8 units of total work.
hence it will take 75/8 days to complete the task.

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vikram kumar patari  (4 years ago)

given
a=30
b=20
c=10
let work =60 unit
a=2unit/day
b=3unit/day
c=6unit/day
according to question a+b come than a+c
a+b=5unit/day
a+c=8unit/day
we have 1 tuples (5+8)/2day
13unit/2day
we have total work 60 unit
than we to take 60/13=4*2=8day
and remaining 8 unit 1 day cover a+b=5 unit and remaining 3 unit (a+c) and we know that a+c in one day finish 8 unit so 3 unit take 3/8 day
so overall ans=8+1+3/8 =75/8 and

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Annu  (6 years ago)

A will be doing 2unit/day
B will be 3 and C will be 6.
Now total work done has to be 60Units ( lcm of 30,20,10)

On day 1 : a +b = 5
on day 2 : a + c = 8
Total 13 in 2 days
No. of Sets : 60/13 = 4.6 approx
Set of 2, So : 4.6*2 =9.2 Days

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