Latest tcs Aptitude Question SOLUTION: There are 10 person among whom two are brother. The total number of ways in which these persons can be seated around a round table so that exactly one person sit between the brothe

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There are 10 person among whom two are brother. The total number of ways in which these persons can be seated around a round table so that exactly one person sit between the brothers , is equal to:

Asked In tcs sangeethatamilselvan (7 years ago)

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Read Solution (13) :

Nandini  (7 years ago)

2*7!*8
Two brothers can be arranged in 2 ways.
In the middle of 2 brothers, any of 8 other person can sit, so 8 ways.
The rest 7 people can be arranged in 7! Ways.
So, 7!*2*8

Is this solution Helpfull? Yes (19) | No (6)  

GOPALAKRISHNAN  (7 years ago)

Total number of ways = 7!*2!

Is this solution Helpfull? Yes (6) | No (3)  

Shashank Sourabh Singh  (7 years ago)

answer: 2*8!
seating of two brothers in rounded table is 2 way.
fix them due to symmetry of rounded table then other 8 person seat by 8!
So 2*8!

Is this solution Helpfull? Yes (3) | No (1)  

sourav1  (7 years ago)

Total number of ways = 8c1*2!

Is this solution Helpfull? Yes (2) | No (3)  

Belgewar Raju  (7 years ago)

we have to fix a position of either brother1 or brother2 so,no.of ways that bros arranged =2!
and remaining 8 are arranged in 8! ways .
total=2!*8!

Is this solution Helpfull? Yes (2) | No (1)  

alekhya  (6 years ago)

2 brothers seated in 2! ways
In between brothers seated in 8C1 ways and reaming will be seated in 7!ways
hence 2!*8*7!

Is this solution Helpfull? Yes (1) | No   

Raji Vanam  (7 years ago)

2*8!

If we fix one brother's position fixed, other brother can be left/right of his brother, so number of ways = 2
The number of ways to sit for 8 persons = 8!
Overall number of ways = 2*8!

Is this solution Helpfull? Yes | No (2)  

PRAVAR  (7 years ago)

7C1*7C3*2!

Is this solution Helpfull? Yes | No (2)  

  (6 years ago)

Let us fix one person called P and the two brothers called X and Y. So let’s form a group of two brothers and one person X P Y . Hence person is fixed in middle and 2 ways to arrange two brothers X P Y and Y P X.
Now, assuming total people = 17 (17 people and 1 group of X,Y and P). So arrangement = 17!


Each person out of 18 can be fixed between the two=18

Final answer = 2∗17!∗18=2∗18!

Is this solution Helpfull? Yes | No (4)  

Surya Nagendra  (6 years ago)

2*8*7!
Two brothers 2 ways
One place between brothers 8 ways
Remaining 7 placed 7! Ways

Is this solution Helpfull? Yes | No (2)  

PRAVIN  (6 years ago)

2!*7!====because 2 brothers are fixed besides one fixed person and they can be arranged in 2! ways and the remaning 7 peoples can be arrange in 7! ways.

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Prikshit Gakhar  (6 years ago)

18!*2
Correct one

Is this solution Helpfull? Yes | No (1)  

Pavani  (3 years ago)

Let consider 2 brothers and middle person as 1 unit so total members =8
No.of ways =(n-1)!
=7!
And two brothers can be seated in 2! Ways
Total no of ways = 7!*2!

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